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Alex
4 years ago
14

(12 points) When forces are UNBALANCED on an object, the object could: (Choose all that apply)

Physics
1 answer:
charle [14.2K]4 years ago
7 0

As per Newton's law when unbalanced force is acting on the object

F = ma

so acceleration of the object is given as

a = \frac{F}{m}

since object is accelerating here so we can say that due to unbalanced force there must be change in velocity of the object

So correct answer regarding change in velocity must be given as

<u>3. Decelerate </u>

<u>4. Stop moving </u>

<u>5. Accelerate </u>

<u>7. Start moving</u>

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A 5 cm spring is suspended with a mass of 1 g attached to it which extends the spring by 3.2 cm. The same spring is placed on a
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First, we need to find the spring constant

Force of gravity = force of tension from spring

mg = kx

(1x10^-3)(9.8) = k (3.2x10^-2)

k = .30625

Now we can look at the other situation

Since the spring was moved 0.01 meters, we can find the force

F = kx = (.01)(.30625) = .0030625 N

Now we can set the electric force equal to the force of the beads

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5 0
1 year ago
Compared to yellow light, orange light has A. a shorter wavelength. B. a wavelength closer to that of gamma rays. C. the same fr
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D. A longer Wavelength
7 0
3 years ago
Find the volume of cuboid of side 4cm. Convert it in SI form​
MAXImum [283]

Answer:

0.000064 cubic meters.

Explanation:

Given the following data;

Length of side = 4 centimeters

Conversion:

100 centimeters = 1 meters

4 cm = 4/100 = 0.04 meters

To find the volume of cuboid;

Mathematically, the volume of a cuboid is given by the formula;

Volume of cuboid = length * width * height

However, when all the sides are equal the formula is;

Volume of cuboid = L³

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Volume of cuboid = 0.000064 cubic meters.

6 0
3 years ago
A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end
Natalka [10]

Answer:

The angular acceleration α = 14.7 rad/s²

Explanation:

The torque on the rod τ = Iα where I = moment of inertia of rod = mL²/12 where m =mass of rod  and L = length of rod = 4.00 m. α = angular acceleration of rod

Also, τ = Wr where W = weight of rod = mg and r = center of mass of rod = L/2.

So Iα = Wr

Substituting the value of the variables, we have

mL²α/12 = mgL/2

Simplifying by dividing through by mL, we have

mL²α/12mL = mgL/2mL

Lα/12 = g/2

multiplying both sides by 12, we have

Lα/12 × 12 = g/2 × 12

αL = 6g

α = 6g/L

α = 6 × 9.8 m/s² ÷ 4.00 m

α = 58.8 m/s² ÷ 4.00 m

α = 14.7 rad/s²

So, the angular acceleration α = 14.7 rad/s²

5 0
3 years ago
Explain how the gas laws apply to the act of breathing. Describe the changes that occur in each step of the process in terms of
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<span>When you in inhale, you move your diaphragm down increasing the volume of the cavity in your ribs (its called pleural cavity). This lowers the pressure inside your lungs. When the pressure in your lungs is less than the atmospheric pressure, air draws inwards. Ideal gas law: PV=nRT -> assume nRT are constant for our purposes. then we allow one system to be equal to the same system at different conditions, thus: P1V1=P2V2 (Boyles Law) assume P1=1 atm and V1=1 L (keeping the numbers simple to avoid confusion). when the V is increased (for example say doubled) V2=2 L, then: (1 atm)*(1 L)=P2*(2 L) -> P2=0.5 atm The pressure was decreased. Apply the same logic for exhalation.</span>
4 0
3 years ago
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