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ra1l [238]
3 years ago
14

A pendulum takes 10 seconds to swing through 2 complete cycles.

Physics
2 answers:
Anvisha [2.4K]3 years ago
4 0
A) 5 seconds
b) same meaning as a)
c) 0.2 Hz (1/5)
Readme [11.4K]3 years ago
3 0

Answer:

a. 5 seconds

b. 5 seconds

c. 0.2 Hz

Explanation:

a) For 2 complete cycles, time taken is 10 s.

Thus, for 1 complete cycle, the pendulum would take = 10 s÷ 2 = 5 s

b) The time period of a pendulum can be defined as time to complete 1 cycle/oscillation. This is calculated in part a. Thus, time period of the pendulum is 5 s.

c) The frequency of a pendulum can be define number of cycles/oscillations in 1 s. It takes 5 s to complete 1 cycle.

In 1 s, number of cycles = (1 ÷ 5) s⁻¹ = 0.2 Hz.

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Compare the strengths of UV light and microwaves (in Hz). Which type of light is more powerful and how do you know?
TEA [102]

Answer:

UV light is more powerful as it has greater energy.

Explanation:

The energy propagated by electromagnetic waves ( light ) through vacuum or medium is known as electromagnetic radiation.

The frequency/wavelength range of electromagnetic radiation is known as electromagnetic spectrum. The electromagnetic spectrum ranging from gamma ray to radio waves.

Frequency range of UV light = ( 8 x 10¹⁴ to 3 x 10¹⁶ ) Hz

Frequency range of Microwaves = ( 300 x 10⁶ to 300 x 10⁹ ) Hz

Ratio of UV light to Microwaves = (\frac{8\times10^{14} }{300\times10^{6} } to \frac{3\times10^{16} }{300\times10^{9} } )

                                                     = ( 2.66 x 10⁶ to 1 x 10⁸ )

Energy of electromagnetic radiation is given by the relation:

E = hν

Here h is plank's constant and ν is frequency.

UV light is more powerful than Microwaves as frequency of UV light is greater than frequency of microwaves. Thus, by the above equation, the energy of UV light is more than energy of Microwaves.  

5 0
4 years ago
An archer tests various arrowheads by shooting arrows at a pumpkin that is suspended from a tree branch by a rope, as shown to t
erik [133]

Answer:

Bounce 1 ,  pass 3,   emb2

Explanation:

(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle.  So it is  Bounce1, pass3, emb2.  

6 0
3 years ago
Put a ball on the floor what forces are acting on it
In-s [12.5K]

Answer: Gravity

Explanation: Gravity is pulling down on the ball, making it stay on the floor

8 0
4 years ago
Which of the following are basic principles that apply to circuits? Choose the 2 correct answers from the choices below.
marta [7]

The basic principles that apply to circuits is that electrons must receive energy from a source, and electrons transfer energy to perform some useful function.

<h3 /><h3>What is circuit?</h3>

Individual electronic components, like resistors, transistors, are connected by metallic wires or traces by which the electric current can flow to form a circuit design.

The basic principles that apply to circuits will be;

1. Electrons must receive energy from a source.

2. Electrons transfer energy to perform some useful function.

Hence, option 1 and 2 are correct.

To learn more about the circuit, refer to the link;

brainly.com/question/21505732

#SPJ1

5 0
2 years ago
A bar magnet is held above the center of a conducting ring in the horizontal plane. The magnet is dropped so it falls lengthwise
Alenkinab [10]

Explanation:

Since, it is given that the magnet drops and falls lengthwise towards the canter of the ring. As a result, change in magnetic flux will occur which tends to induce an electric current in the ring.

Therefore, a magnetic field is also produced by the ring itself which will actually oppose or repel the magnet.  

Thus, we can conclude that the falling magnet be repelled by the ring due to the magnetic interaction of the magnet and the ring.

7 0
3 years ago
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