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madreJ [45]
3 years ago
12

How did the development of the earliest idea about atoms differ from the later work of scientists?

Chemistry
2 answers:
IgorLugansk [536]3 years ago
8 0
The earliest idea of the atom is that it is made up of tiny, invisible particles, called the atoms, is believed to have originated from the Greek philosopher Leucippus of Miletus and his student, Democritus of Abdera, around 5th century B.C. However, it wasn't until centuries later that the atomic theory was taken seriously by the society, thanks to the scientist John Dalton by 1808. Hence, the development of the Atomic Theory began until the modern age. Modern scientist has more technological advancements than the early age. Therefore, the modern scientist can view the atom more detailed than before.

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Igoryamba3 years ago
7 0

Answer:

The smallest unit of matter, which possesses the characteristics of an element is known as an atom. It comprises a dense core known as the nucleus and alignment of outer shells inhabited by orbiting electrons.  

The early concepts of the atom postulate that the atom is a solid or a hollow body comprising nothing within. However, the discoveries and work done by scientists afterward have proved that the atoms comprise the subatomic constituents, that is, the protons, electrons, and neutrons.  

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When both –NH2 and –COOH replace hydrogen atoms on the same carbon atom, a(n) ____ is formed. a. amine c. carboxylic acid b. ami
Mice21 [21]

-NH_{2} represents amine functional group and COOH represents carboxylic acid functional group. When these both functional groups are substituted onto a single carbon atom, then amino acid is formed.

The organic compound consists of -NH_{2} functional group and COOH functional group with a side chain is said to be an amino acid.

A: amine group is -NH_{2}.

C: carboxylic acid  group is COOH

B: amino acid represents -NH_{2} functional group and COOH functional group which are substituted onto a single carbon atom.

D: carbohydrate:  the general formula of carbohydrate is (CH_{2} O)_{x}.

Hence, amino acid is the correct answer.





4 0
3 years ago
How many grams of iron can be obtained from a 268g sample of iron(III) oxide?
Nikolay [14]

Answer:187

Explanation:

5 0
4 years ago
Which statements describe surface waves? Check all that apply.
neonofarm [45]

Answer:

The correct answers are "They travel slower than P waves", "They result in much ground motion" and " They are produced by P and S waves".

Explanation:

A surface wave can travel through the existing interface between Earth and air, as well as between Earth and water. A clear example of this type of waves are Love and Rayleigh waves. They travel slower than primary waves, produce large movements in the ground and are produced by primary and secondary waves.

Have a nice day!

3 0
3 years ago
Which molecule has polar bonding and is nonpolar? A. H2O B. BF3 C. NH3 D. NCl3 E. CH2Cl2
Marina CMI [18]

Answer:

B. BF₃

Explanation:

All the molecules have polar bonds, but a molecule will be nonpolar if the molecule has the symmetry that makes the bond dipoles cancel.

To make the decision, we must

  1. Draw the Lewis structure
  2. Assign the VSEPR electron geometry
  3. Determine the molecular shape.
  4. Examine the symmetry of the molecule

===============

<em>A. Water </em>

Lewis structure = H-O-H (2 bonding pairs, 2 lone pairs)

Electron geometry = AX₂E₂ tetrahedral

Molecular geometry = bent

Symmetry (see Figure A): The two O-H bonds are polar, with their negative ends pointing towards the O. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give an upward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>B. Boron trifluoride </em>

Lewis structure = BF₃ (3 bonding pairs)

Electron geometry = AX₃, trigonal planar

Molecular geometry = trigonal planar

Symmetry (see Figure B): The three B-F bonds are polar, with their negative ends pointing towards the F. The horizontal components of the bond dipoles cancel, but the vertical components of the two downward -pointing dipoles reinforce each other and give a resultant that is equal and opposite to the upward dipole. Thus, the bond dipoles cancel. This is a nonpolar molecule with polar bonds.

===============

<em>C. Ammonia</em>

Lewis structure = :NH₃ (3 bonding pairs, 1 lone pairs)

Electron geometry = AX₃E, tetrahedral

Molecular geometry = trigonal pyramidal

Symmetry (see Figure C): The three N-H bonds are polar, with their negative ends pointing towards the N. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give an upward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>D. Nitrogen trichloride </em>

Lewis structure = :NCl₃ (3 bonding pairs, 1 lone pair)

Electron geometry = AX₃E, tetrahedral

Molecular geometry = trigonal pyramidal

Symmetry (see Figure D): The three N-Cl bonds are polar, with their negative ends pointing towards the Cl. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give a downward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>E. Dichloromethane </em>

Lewis structure = H₂CCl₂ (4 bonding pairs)

Electron geometry = AX₄, tetrahedral

Molecular geometry = tetrahedral

Symmetry (see Figure E): The two C-H bonds are nonpolar, but the two C-Cl bonds are polar with their negative ends pointing towards the Cl. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give a downward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

3 0
4 years ago
: Calculate molar mass of the following compounds:
lozanna [386]

Answer:

1. 58.5g/mol

2. 261g/mol

3. 158g/mol

4. 71g/mol

5. 44g/mol

Explanation:

The molar mass of a compound is the total mass of the sum of masses of all individual elements that make up the compound. First, we need to know the atomic masses of each element in a compound.

1. NaCl

Where; Na = 23, and Cl = 35.5

Molar mass of NaCl = 23 + 35.5

= 58.5g/mol

2. Ba(NO3)2:

Where; Ba = 137, N = 14, O = 16

Molar mass of Ba(NO3)2: 137 + {14 + 16(3)} 2

137 + (14 + 48)2

137 + (62)2

137 + 124

= 261g/mol

3. K(MnO4)

Where; K = 39, Mn = 55, O = 16

Molar mass of KMnO4 = 39 + 55 + 16(4)

= 94 + 64

= 158g/mol

4. Cl2

Where; Cl = 35.5

Molar mass of Cl2 = 35.5(2)

= 71g/mol

5. CO2

Where; C = 12, O = 16

Molar Mass of CO2 = 12 + 16(2)

= 12 + 32

= 44g/mol

3 0
3 years ago
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