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zloy xaker [14]
3 years ago
10

Based on the data table, which unknown solution could be 0.1 m naoh

Chemistry
1 answer:
Aliun [14]3 years ago
3 0

Answer:

Where is the data table?

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Which of the following is not the same as 12.5 millimeters? 0.0000125 km 0.00125 hm 0.0125 m 1.25 cm
erma4kov [3.2K]
1 mm (millimeter) = 0.000001 km (kilometer)
12.5 mm = <span>0.0000125 km

1 mm = </span><span>0.00001 hm (hectometer)
12.5 mm = </span><span>0.000125 hm

1 mm = </span>0.001 m (meter)
12.5 mm = 0.0125 m

1 mm = 0.1 cm (centimeter)
12.5 mm = 1.25 cm

So the only one of the answer choices that doesn't equal 12.5 mm is 0.00125 hm, since 12.5 mm is <span>0.000125 hm.

Answer:
</span><span>0.00125 hm
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Saturated fats are typically liquid at room temperature. saturated fats are typically liquid at room temperature.
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Calculate to three significant digits the density of chlorine pentafluoride gas at exactly and exactly . You can assume chlorine
slega [8]

Answer:

Density is 6.16g/L

Explanation:

<em>... at exactly -15°C and exactly 1atm...</em>

<em />

Using general gas law:

PV = nRT

We can find density (Ratio of mass and volume) in an ideal gas as follows:

P/RT = n/V

<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>

n*MW = m

n = m/MW

P/RT = m/V*MW

P*MW/RT = m/V

<em>Where P is pressure: 1atm;</em>

<em>MW of chlorine pentafluoride: 130.445g/mol</em>

<em>R is gas constant: 0.082atmL/molK</em>

<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>

<em />

Replacing:

P*MW/RT = m/V

1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V

6.16g/L = m/V

<h3>Density of the gas is 6.16g/L</h3>

<em> </em>

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