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n200080 [17]
3 years ago
6

A solid metal sphere with radius 0.430 m carries a net charge of 0.270 nC . Part A Find the magnitude of the electric field at a

point 0.106 m outside the surface of the sphere. Express your answer using three significant figures. E
Physics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

8.46 N/C

Explanation:

Using Gauss law

E=\frac {kQ}{r^{2}}

Gauss's Law states that the electric flux through a surface is proportional to the net charge in the surface, and that the electric field E of a point charge Q at a distance r from the charge

Here, K is Coulomb's constant whose value is 9\times 10^{9} Nm^{2}/C^{2}

r = 0.43 + 0.106 = 0.536 m

E=\frac {9\times 10^{9}\times 0.270\times 10^{-9}}{0.536^{2}}=8.4581755402094007\approx 8.46 N/C

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Answer:

Explanation:

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vlada-n [284]

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2 years ago
A wire loop of radius 0.50 m lies so that an external magnetic field of magnitude 0.40 T is perpendicular to the loop. The field
vazorg [7]

The magnitude of the induced emf is given by:

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