QUESTION 1
The given logarithmic expression is

We rewrite
in the index form to base 4.
This implies that;

We now apply the power rule:
.

Recall that logarithm of the base is 1.


QUESTION 2
The given logarithm is;
![\log_2(\sqrt[5]{32})](https://tex.z-dn.net/?f=%5Clog_2%28%5Csqrt%5B5%5D%7B32%7D%29)
![\log_2(\sqrt[5]{2^5})](https://tex.z-dn.net/?f=%5Clog_2%28%5Csqrt%5B5%5D%7B2%5E5%7D%29)
This is the same as;



Answer:
(y+7x^3) (y-7x^3)
Step-by-step explanation:
Surface area I think is the circle. So the formula to find the area of the circle is to do Pi times radius squared. Pi= 3.14 Radius in this case will be 2.2. (Radius is how much it measures out from the middle.) then you want to do 2.2 x 2.2 (since it's square) So the answer would be equal to (I think) 15.1976