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Vedmedyk [2.9K]
3 years ago
11

Can some one work out this equation for me :)

Chemistry
1 answer:
Law Incorporation [45]3 years ago
4 0

Yo sup??

CaCO3 + 2 HCl ---------> CaCl2 + H2O + CO2

This is the balanced chemical equation

Hope this helps

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If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
Aleonysh [2.5K]

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

M(N2) = 2*14 = 28 g/mol

M(NH3) = 14 + 3*1 = 17 g/mol

23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

8 0
4 years ago
. Which information is NOT included in each square of the periodic table in your text? a. atomic number c. melting point b. chem
azamat
The correct answer is melting point
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Katyanochek1 [597]

Answer:

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And thus we get the quotient:

128.3⋅g16.04⋅g⋅mol−1=8.0⋅moles of methane.

Note that the expression is dimensionally consistent, we wanted an answer in moles, and the quotients gives, 1mol−1=11mol=mol as required.

6 0
3 years ago
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