Answer:8.28 km
Explanation:
Given
First it drifts 
2.5 km
Secondly it drifts 
4.70 km
After that it drifted along east direction 5.1 km
After that it drifts 
7.2 km
After that it drifts 
2.8 km
=![\left [ 2.5cos45+4.7cos60+5.1-7.2cos55-2.8cos5\right ]\hat{i}](https://tex.z-dn.net/?f=%5Cleft%20%5B%202.5cos45%2B4.7cos60%2B5.1-7.2cos55-2.8cos5%5Cright%20%5D%5Chat%7Bi%7D)
+![\left [ 2.5sin45-4.7sin60-7.2sin55+2.8sin5\right ]\hat{j}](https://tex.z-dn.net/?f=%5Cleft%20%5B%202.5sin45-4.7sin60-7.2sin55%2B2.8sin5%5Cright%20%5D%5Chat%7Bj%7D)
for direction
south of east
Answer:
26.822 m/s
Explanation:
60 mi/hr * 5280 ft/mile * 1 hr / 3600 sec * 12 in / foot * 1 meter / 39.37 in = <u>26.822 m/s</u>
Answer:
Explanation:
⁵⁷Co₂₇ + e⁻¹ = ²⁷Fe₂₆
mass defect = 56.936296 + .00055 - 56.935399
= .001447 u
equivalent energy
= 931.5 x .001447 MeV
= 1.3479 MeV .
= 1.35 MeV
energy of gamma ray photons = .14 + .017
= .157 MeV .
Rest of the energy goes to neutrino .
energy going to neutrino .
= 1.35 - .157
= 1.193 MeV.
The object's mass is around 69.592 kg
F=mg
