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nevsk [136]
3 years ago
12

Which of the following is an example of benefits?

Physics
1 answer:
dangina [55]3 years ago
6 0
Insurance would be a example of benefits because you don’t receive insurance like you would salary, salary is a base thing you receive when you get a job while insurance you only get as a benefit with certain jobs
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⚠Heeeeeelelepelepleplepelepeplepe⚠
snow_tiger [21]

Answer:

It's B, anything about a circle is Stationary

4 0
3 years ago
Glare appears on a computer screen when light from the surroundings reflects off of the screen’s surface. Some computer screens
hoa [83]

Answer:

The correct answer is D.

D:The surface of the coating allows light from the room to pass through but blocks the light from the screen.

Explanation:

Glare is produced on a computer screen when light from some external source reflects on the screen.

Anti-glare coating do not absorb light to reduce glare but they actually reduce glare by encouraging the light from the room to pass through the screen so that less light is reflected. Polarized lenses absorbs light to reduce glare, not anti-glare coating.

7 0
2 years ago
Read 2 more answers
If the amplitude of a wave is increased the frequency of the wave will
Travka [436]

Answer:

Remain the same

Explanation:

There is no relationship between amplitude frequency.

3 0
2 years ago
A testable question about what would happen if you fell into a black hole
daser333 [38]

Answer:

You wouldnt fall you would be sucked and you would lose all air supply and you lungs would pop

Explanation:

7 0
2 years ago
The planet Krypton has a mass of 8.8 × 1023 kg and radius of 2.5 × 106 m. What is the acceleration of an object in free fall nea
djverab [1.8K]

Answer:

Acceleration, a=9.39\ m/s^2

Explanation:

Given that,

Mass of the planet Krypton, m=8.8\times 10^{23}\ kg

Radius of the planet Krypton, r=2.5\times 10^{6}\ m

Value of gravitational constant, G=6.6726\times 10^{-11}\ Nm^2/kg^2

To find,

The acceleration of an object in free fall near the surface of Krypton.

Solution,

The relation for the acceleration of the object is given by the below formula as :

a=\dfrac{Gm}{r^2}

a=\dfrac{6.6726\times 10^{-11}\times 8.8\times 10^{23}}{(2.5\times 10^{6})^2}

a=9.39\ m/s^2

So, the value of acceleration of an object in free fall near the surface of Krypton is 9.39\ m/s^2

5 0
3 years ago
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