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3 years ago

Which of the following is an example of benefits?

1 answer:

6 0

Insurance would be a example of benefits because you don’t receive insurance like you would salary, salary is a base thing you receive when you get a job while insurance you only get as a benefit with certain jobs

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Ignoring reflection at the air-water boundary, if the amplitude of a 10 GHz incident wave in air is 20 V/m at the water surface,

dimaraw [331]

Answer:

0.80267 m

Explanation:

E(z) = Electric field = 1 µV/m

$E_0$ = 20 V/m

z = Depth

$\sigma$ = Conductivity = 0.1 S/m

$\epsilon_r$ = 81

$\mu$ = Impedance of free space = $120\pi\ \Omega$

Frequency is given by

$E(z)=E_0e^{-\alpha z}$

Parameter is given by

$\alpha=\dfrac{\sigma}{2}\sqrt{\dfrac{\mu}{\epsilon_r}}\\\Rightarrow \alpha=\dfrac{1}{2}\sqrt{\dfrac{(120\pi)^2}{81}}\\\Rightarrow \alpha=20.94395\ N_p/m$

From the first equation

$1\times 10^{-6}=20e^{-20.94395z}\\\Rightarrow ln\dfrac{1\times 10^{-6}}{20}=-20.94395z\\\Rightarrow z=\dfrac{ln\dfrac{1\times 10^{-6}}{20}}{-20.94395}\\\Rightarrow z=0.80267\ m$

The depth is 0.80267 m

7 0

3 years ago

when the c4 key on a piano keyboard is pressed, a string inside the piano is struck by a hammer and begins vibrating back and fo

Ugo [173]

The correct answer is f= 260 Hz

7 0

3 years ago

Read 2 more answers

What else is produced when sodium carbonate decomposes?

kompoz [17]

Answer: What else is produced when sodium carbonate decomposes?

Explanation:

3 0

2 years ago

Read 2 more answers

When a submarine dives to a depth of 5.0 × 102 m, how much pressure, in pa, must its hull be able to withstand? how many times l

nordsb [41]

<span>Depth = 5.0 Ă— 10^2 m
Density of sea water = 1.025 x 10^3
Pd = Po + pgh
Atmospheric pressure is standard Patm = 1.01325 x 10^5 Pa
Since the normal pressure is retained in the hull, no need to bother about Po Pd = pgh = 1.025 x 10^3 x 9.8 x 5.0 x 10^2 = 50.225 x 10^5
So now Pd / Patm = 50.225 x 10^5 / 1.01325 x 10^5 = 49.56
So it is 49.56 times larger.</span>

5 0

3 years ago

Read 2 more answers

Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m

Reil [10]

Answer:

$\Delta l=0.015m$