A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?
1 answer:
The change in momentum of the car is 45,000 kg m/s
Explanation:
The change in momentum of an object is given by:
where
m is the mass of the object
u is its initial velocity
v is its final velocity
For the car in this problem, we have
m = 900 kg
u = 30 m/s
v = 80 m/s
Therefore, the change in momentum is:
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Answer:
Explanation:
Check attachment
Answer
In this question we have given,
Height of plane, h1=2000m
Height at which charge concentration is 40C, h2=3000m
Height at which charge concentration is -40C, h3=1000m
charge concentaration, q1=40C
charge concentaration, q2=-40C
let the charge concentrations at height h2 and h3 as point charges
Now we will first find the electric feild on plane due to positive charge q1=40
Here k=8.98755*10^9N.m^2/C^2
q1=40C
put values of k, q1 , h1 and h2 in equation 1
\\
V/m[/tex]
similarly electric feild due to negative charge q2=-40
\\
Total electric feild E at the aircraft is given as
...............(2)
Put values of E1 and E2 in equation2
therefore s Total electric feild E at the aircraft is E= 719004V/m