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3 years ago

A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?

Physics

1 answer:

AlexFokin [52]3 years ago

3 0

The change in momentum of the car is 45,000 kg m/s

Explanation:

The change in momentum of an object is given by:

$\Delta p = m(v-u)$

where

m is the mass of the object

u is its initial velocity

v is its final velocity

For the car in this problem, we have

m = 900 kg

u = 30 m/s

v = 80 m/s

Therefore, the change in momentum is:

$\Delta p = (900)(80-30)=45,000 kg m/s$

Learn more about momentum:

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3 years ago

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Answer:

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

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d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

Explanation:

The statement is incomplete. We proceed to present the complete statement: A block attached to a spring with unknown spring constant oscillates with a period of 2.00 s. What is the period if a. The mass is doubled? b. The mass is halved? c. The amplitude is doubled? d. The spring constant is doubled?

We have a block-spring system, whose angular frequency ( $\omega$ ) is defined by the following formula:

$\omega = \sqrt{\frac{k}{m} }$ (1)

Where:

$k$ - Spring constant, measured in newtons per meter.

$m$ - Mass, measured in kilograms.

And the period ( $T$ ), measured in seconds, is determined by the following expression:

$T = \frac{2\pi}{\omega}$ (2)

By applying (1) in (2), we get the following formula:

$T = 2\pi\cdot \sqrt{\frac{m}{k} }$

a) If the mass is doubled, then the period is increased by $\sqrt{2}$ . Hence, the period of the system is 2.828 seconds.

b) If the mass is halved, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

c) The period of the system does not depend on amplitude. Hence, the period of the system is 2 seconds.

d) If the spring constant is doubled, then the period is reduced by $\frac{\sqrt{2}}{2}$ . Hence, the period of the system is 1.414 seconds.

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3 years ago

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Answer:

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Explanation:

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Height,h=1.8 m

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2 years ago

A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?​

A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?