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3 years ago

A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?

Physics

1 answer:

AlexFokin [52]3 years ago

3 0

The change in momentum of the car is 45,000 kg m/s

Explanation:

The change in momentum of an object is given by:

$\Delta p = m(v-u)$

where

m is the mass of the object

u is its initial velocity

v is its final velocity

For the car in this problem, we have

m = 900 kg

u = 30 m/s

v = 80 m/s

Therefore, the change in momentum is:

$\Delta p = (900)(80-30)=45,000 kg m/s$

Learn more about momentum:

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Explanation:

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3 years ago

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Answer:

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Explanation:

In the double-slit interference phenomenon it is explained for constructive interference by the equation

d sin θ = m λ

1) the first order maximum occurs for m = 1

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θ = sin⁻¹ λ / d

let's reduce the magnitudes to the SI system

λ = 520 nm = 520 10⁻⁹ θ = 0.00118 radm

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let's calculate

θ = sin⁻¹ (520 10⁻⁹ / 0.44 10⁻³)

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θ = 0.00236 rad

3) To calculate the intensity of the interference spectrum, the diffraction phenomenon must be included, so the equation remains

I = I₀ cos² (π d sin θ /λ ) sinc² (pi b sin θ /λ )

where the function sinc = sin x / x

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we caption the values

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remember angles are in radians

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I / I₀ = 0.1738

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I / I₀ = cos² (π d sinθ / λ) sinc² (πb sin θ /λ)

x =π 0.310 10⁻³ sin 0.00236 / 520 10⁻⁹)

x = 4.41

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A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?​

A 900 kg car speeds up from 30 M/S to 80 m/s how much momentum did the car gain?