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fgiga [73]
3 years ago
7

The distance between two successive crests of a certain transverse wave is 1.40 m. 25 crests pass a given point along the direct

ion of travel every 12.4 s. Calculate the wave speed. Answer in units of m/s.
Physics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer: 2.82m/s

Explanation:

Wave speed(v) is the product of the frequency (f) of a wave and its wavelength (¶)

V = f¶

Since wavelength is the distance between two successive crests or trough, the wavelength given is 1.40m i.e ¶ = 1.40m

If the total crest is 25, this means that 25 oscillations occurs in 12.4s.

Since the number of oscillation made in one second is the frequency, frequency = 25/12.4 = 2.01cycle/seconds

Speed of the wave v = 2.01×1.4

V =

Wave speed is 2.82m/s

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One possible question can be:

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The answer to this question is contained in Charle's law, which states that for a gas at constant pressure, the volume of the gas is proportional to its absolute temperature:

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