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fgiga [73]
3 years ago
7

The distance between two successive crests of a certain transverse wave is 1.40 m. 25 crests pass a given point along the direct

ion of travel every 12.4 s. Calculate the wave speed. Answer in units of m/s.
Physics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer: 2.82m/s

Explanation:

Wave speed(v) is the product of the frequency (f) of a wave and its wavelength (¶)

V = f¶

Since wavelength is the distance between two successive crests or trough, the wavelength given is 1.40m i.e ¶ = 1.40m

If the total crest is 25, this means that 25 oscillations occurs in 12.4s.

Since the number of oscillation made in one second is the frequency, frequency = 25/12.4 = 2.01cycle/seconds

Speed of the wave v = 2.01×1.4

V =

Wave speed is 2.82m/s

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You have four fixed-volume containers at STP . Container A has 0.5 mol of gas in 11.2 L. Container B has 2 mol of gas in 22.4 L.
Colt1911 [192]

Answer:

Container A and C

Explanation:

ideal gas equation gives P=nRT/V

so at constant Temperature and pressure, P=n/T

Container A and C after dividing number of moles and Volume, are found to be the same=0.0446

8 0
3 years ago
What is the surface area?
OleMash [197]

Answer:

Surface area is the amount of space covering the outside of a three-dimensional shape.

I hope this help, if not I am sorry.

5 0
2 years ago
Read 2 more answers
A mechanic changing the spark plugs in a car notes that the instruction manual calls for a torque with a magnitude of
Papessa [141]

The magnitude (in N) of the force she must exert on the wrench is 150.1 N.

<h3>Force exerted by the wrench</h3>

The force exerted by the wrench is calculated using torque formula as follows;

torque, τ = F x r x sinθ

where;

  • F is the applied force
  • r is the perpendicular distance if force applied

F =  τ /(r sinθ)

F = (39) / (0.3 sin 60)

F = 150.1 N

Thus, the magnitude (in N) of the force she must exert on the wrench is 150.1 N.

Learn more about torque here: brainly.com/question/14839816

#SPJ1

5 0
1 year ago
For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
3 years ago
A shuttle on Earth has a mass of 4.5 E 5 kg. Compare its weight on Earth to its weight while in orbit at a height of 6.3 E 5 met
faltersainse [42]

Answer:

83%

Explanation:

On the surface, the weight is:

W = GMm / R²

where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.

In orbit, the weight is:

w = GMm / (R+h)²

where h is the height of the shuttle above the surface of the Earth.

The ratio is:

w/W = R² / (R+h)²

w/W = (R / (R+h))²

Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:

w/W = (6.4×10⁶ / 7.03×10⁶)²

w/W = 0.83

The shuttle in orbit retains 83% of its weight on Earth.

4 0
3 years ago
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