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photoshop1234 [79]
3 years ago
10

A race car travels 800 kilometers in 2 hours during a race. What was the average speed of the race car in km/hr.

Chemistry
2 answers:
bonufazy [111]3 years ago
5 0
400km/hr. Simply divide total km travelled by the amount of hours it took to find your answer.
Sunny_sXe [5.5K]3 years ago
3 0

Answer:

400

you will get this answer if you do distance divided by time.

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You chill your reaction in an ice bath when adding nitric acid to the sulfuric acid. why?
Andrej [43]
The reaction of nitric acid and sulfuric acid is highly exothermic so it releases a lot of heat. If the temperature is not controlled, the reaction could go into thermal runaway, which is potentially extremely hazardous.
4 0
3 years ago
Why would methane attain a tetrahedral structure?​
lys-0071 [83]

<h2>HOPE THIS HELPS YOU ....</h2><h3>PLEASE MARK ME AS BRAINILIST...</h3>

3 0
3 years ago
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Which statement describe what happens to the kinetic energy of the particles in the atmosphere as they come into contact with th
timurjin [86]

the answer is The average kinetic energy of the surrounding air particles increases.


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7 0
3 years ago
A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
6 0
3 years ago
A solution of citric acid (H₃C₆H₅O₇) with a known concentration of 0.200 M H₃C₆H₅O₇ is titrated with a 0.750 M NaOH solution. Ho
Anestetic [448]

The quantity of NaOH required to reach the third equivalence point is 20mL.

Using the titration formula,

CaVa/CbVb = Na/Nb

Where,

Ca = concentration of citric acid (0.200 M)

Cb = concentration of NaOH (0.750 M)

Va = Volume of citric acid (25.0 mL)

Vb = volume of NaOH (x mL)

Na = number of reacting mole of citric acid (3)

Nb = number of reacting mole of NaOH (1)

Therefore Vb ( x mL) =CaVaNb/CbNa

                                 

 = 0.2× 25×3/0.75 ×1

                                   

= 15/0.75

                   Vb ( x mL) = 20 mL

Learn more here:

brainly.com/question/23631409

8 0
3 years ago
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