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Sonja [21]
3 years ago
9

At STP, the temperature is __ degrees Celcius and __ K. Question 2 options:

Chemistry
1 answer:
aliina [53]3 years ago
7 0
At STP the standard temperature is 273.15 K.

At STP the standard temperature is 0*C
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For the chemical reaction:
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Answer:

Volume of ammonia produced = 398.7 dm³

Explanation:

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Pressure and temperature = standard

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N₂ + 3H₂     →      2NH₃

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PV = nRT

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Now we will compare the moles of ammonia and nitrogen.

               N₂          :         NH₃

                1            :           2

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3 years ago
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

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