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3 years ago

Which statement BEST explains whether or not matter is conserved in this chemical reaction?

2 answers:

8 0

In chemical changes, just as in physical changes, matter is conserved. The difference, in this case, is that the substances before and after the change have different physical and chemical properties.

timurjin [86]3 years ago

4 0

Answer:

D:Matter is not being conserved because there are 11 units in the reactants, one C8H8 and 10 O2, and 12 units in the products, eight CO2 and four H2O, so there is also more mass in the products that in the reactants.

Explanation:

searched up

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Inessa [10]

Answer: the formation of ester is an exothermic reaction.. therefore, decreasing the temperature will make the reaction proceed forward, producing more esters

Explanation:

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4 years ago

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muminat

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Explanation:

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2 years ago

The density of silver is 10.5 g/cm3. what would be the mass (in grams) of a piece of silver that occupies a volume of 23.6 cm3?

Keith_Richards [23]

Hey there : !

density = 10.5 g/cm³

volume = 23.6 cm³

therefore:

D = m / V

10.5 = m / 23.6

m = 10.5 * 23.6

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hope this helps!

6 0

3 years ago

Read 2 more answers

Bromine (Br2) is produced by reacting HBr with O2, with water as a byproduct. The O2 is part of an air (21 mol % O2, 79 mol % N2

Karolina [17]

Answer:

The mole fractions:

$x_{HBr}=\frac{100mol}{318.5}=0.314$

$x_{Br_2}=\frac{78mol}{318.5}=0.245$

$x_{H_2O}=\frac{78mol}{318.5}=0.245$

$x_{O_2}=\frac{62.5mol}{318.5}=0.196$

Explanation:

The reaction described is:

$2 HBr (g) + 1/2 O_2 (g) \longrightarrow Br_2 (g) + H_2O (g)$

The limiting reactant is the HBr (oxygen is in excess).

a) The mass (in moles) balance for this sistem:

$n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *n_{HBr}*0.78$

(the 0.78 is because of the fractional conversion)

$n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *n_{HBr}*1.25$

(the 1.25 is because of the oxygen excess)

$n_{H_2O}=\frac{ 1 mol H_2O}{1 mol Br_2} *n_{Br_2}$

There is only one degree of freedom in this sistem, you can either deffine the moles of HBr you have or the moles of Br2 you want to produce. The other variables are all linked by the equations above.

b) Base of calculation 100 mol of HBr:

$nn_{HBr}=100 mol HBr$