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2 years ago

7

Which statement BEST explains whether or not matter is conserved in this chemical reaction?

2 answers:

Tcecarenko [31]2 years ago

8 0

In chemical changes, just as in physical changes, matter is conserved. The difference, in this case, is that the substances before and after the change have different physical and chemical properties.

timurjin [86]2 years ago

4 0

Answer:

D:Matter is not being conserved because there are 11 units in the reactants, one C8H8 and 10 O2, and 12 units in the products, eight CO2 and four H2O, so there is also more mass in the products that in the reactants.

Explanation:

searched up

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Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.

dmitriy555 [2]

<u>Answer:</u> The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

<u>Explanation:</u>

There are 4 quantum numbers:

Principal Quantum number (n) specifies the energy of the electron in a shell.
Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of $+\frac{1}{2}$ or $-\frac{1}{2}$

Berylium (Be) is the 4th element of periodic table having electronic configuration of $1s^22s^2$

<u>For electrons in 1s-orbital, the quantum numbers can be:</u>

For first electron:

$n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=1\\l=0\\m=0\\s=-\frac{1}{2}$

<u>For electrons in 2s-orbital, the quantum numbers can be:</u>

For first electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}$

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

4 0

3 years ago

Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c

nirvana33 [79]

Answer:

pKb = 10.96

Explanation:

Tartaric acid is a dyprotic acid. It reacts to water like this:

H₂Tart + H₂O ⇄ H₃O⁺ + HTart⁻ Ka1

HTart⁻ + H₂O ⇄ H₃O⁺ + Tart⁻² Ka2

When we anaylse the base, we have

Tart⁻² + H₂O ⇄ OH⁻ + HTart⁻ Kb1

HTart⁻ + H₂O ⇄ OH⁻ + H₂Tart Kb2

Remember that Ka1 . Kb2 = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1 → 1×10⁻¹⁴ / 9.20×10⁻⁴ = 1.08×10⁻¹¹

so pKb = - log Kb2 → - log 1.08×10⁻¹¹ = 10.96

7 0

3 years ago

Read 2 more answers

Which option correctly describes the relative charges and masses of the subatomic particles?

Alina [70]

Answer:

D

Explanation:

D Is The Answer Fella, My Head Hurt Really Bad

3 0

2 years ago

How can you increase the energy of a glass of water?

balu736 [363]

B. Heat is a form of energy so boiling it would increase energy. (I guess)

8 0

3 years ago

What is the value of Avogadro's constant?

diamong [38]

Answer:

6.02214154 x 1023

Explanation:

6 0

3 years ago