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kupik [55]
3 years ago
13

what method can be used to separate parts of liquid mixture wwhen the entire mixture can pass through a filter

Chemistry
2 answers:
KIM [24]3 years ago
5 0
The method that can be used to separate the mixture is DISTILLATION.
Distillation is a separating technique that is used to separate mixture of liquids which have boiling points that are far apart. The mixture will be heated, the liquid with the lowest boiling point will boil over and can be collected over a condenser, thus separating the two liquids.
Maslowich3 years ago
5 0
The method that can be used is distillation because distillation can seperate the substances from liquid mixtures by selective boiling and condensation.
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3 A specific amount of energy is emitted when excited electrons in an atom in a sample of an element return to the ground state.
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5 0
3 years ago
Menthol is a flavoring agent extracted from peppermint oil. it contains c, h, and o. in one combustion analysis, 10.00 mg of the
marishachu [46]
Combustion reaction for menthol is as follows;
CxHyOz + O₂ ---> xCO₂ +  H₂O
Mass of CO₂ formed - 28.16 mg
Therefore number of moles formed - 28.16/ 44 g/mol = 0.64 mmol
Mass of water formed  - 11.53 mg
number of water moles formed - 11.53 mg/18 g/mol = 0.64 mmol
From CO₂,
1 mol of CO₂ - 1 mol of C and 2 mol of O
therefore number of C moles - 0.64 mmol
                                 O moles - 1.28 mmol
from H₂O
1 mol of H₂O - 2 mol of H and 1 mol of O
number of H moles - 1.28 mmol
                 O moles - 0.64 mmol

Mass of menthol initially - 10 mg
in reactions, the masses of products are equal to the masses of reactants. The excess mass to the products formed is due to O₂ in air
Original mass of menthol - 10 mg
mass of water and CO₂ - 11.53 mg + 28.16 mg = 39.69
Difference in mass - 39.69 - 10 = 29.69 mg
This difference comes from O moles in air - 29.69 mg/ 16 g/mol = 1.8556 mmol
then O moles coming from menthol - (1.28 + 0.64) - 1.8556 = 0.064 mmol

In menthol 
C moles - 0.64 mmol
H moles - 1.28 mmol
O moles - 0.064 mmol
ratios of C:H:O
C          H         O
0.64    1.28      0.064
x1000  x1000    x1000 to get whole numbers
640       1280      64
10          20          1
Simplest ratio of C:H:O is 10:20:1
therefore empirical formula of menthol is C₁₀H₂₀O


5 0
3 years ago
Which statement is true about the concentration of the reactants and products in chemical equilibrium?
bulgar [2K]

Answer:

Ans: 2

Explanation:

The concentration of reactants and the concentration of products are constant.  

5 0
2 years ago
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