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beks73 [17]
3 years ago
12

Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass h

as an index of refraction 1.50. after traveling through the glass the light re-emerges into the air. what is the final angle of refraction in air?
Physics
1 answer:
mestny [16]3 years ago
4 0
<span>Answer: sin(incidence)/sin(refraction) = n_refraction/n_incidence sin(50) / sin(x) = 1.5 / 1 sin(50)/1.5 = sin(x) sin(x) = 0.511 x = 30.71o B] 50 degrees, same as the angle going in. You can show that by reversing the steps in A. sin(30.7)/sin(x) = 1/1.5 C] The glass is 5 cm thick. The reference angle = 30.7o Tan(30.7) = displacement / thickness Tan(30.7) = x / 5 5*sin(30.7) = x x = 2.97 cm which is the displacement.</span>
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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 39 points and will give branlist asap!
xz_007 [3.2K]

Answer:

Graph for object that is not moving: B

Graph for object that is speeding up: D

Explanation:

A.) In order to represent that an object is not moving, you must either show that there is no velocity (0 m/s) or show a position over time graph that is a horizontal line.

Because the position is the same as time increases, the graph shows that there the object must be at rest, as there is no change in position due to velocity. (Velocity must be 0m/s)

B.) In order to represent an object is speeding up, the position time graph must either be a positive exponential function, the velocity time graph must be a positive, linear line, or the acceleration over time graph must be a positive, horizontal line.

Why is D the correct answer? Because if an object is speeding up, you know that the value of its speed (velocity) is increasing at some rate. And since speeding up refers to positive change, the function of velocity over time graph must be a positive function.

7 0
3 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 3 kg , up an incline of constant slope angle
denis23 [38]

Answer:

v = 9.04 m / s

Explanation:

For this exercise we can use the relation that the work of the non-conservative force (friction) is equal to the variation of the mechanical energy of the system.

          W = Em_f - Em₀         (1)

Starting point. Lower slope

        Em₀ = K = ½ m v²

highest point. Where is the skier at a height h

        Em_f = U = m g h

The work of rubbing

        W = -fr x

the negative sign is because the friction force opposes the movement.

Let's set a reference system where the x axis is parallel to the slope and the y axis is perpendicular

let's use trigonometry to break down the weight

        cos θ = W_y / W

        sin θ = Wₓ / W

        W_y = W cos θ

        Wₓ = W sin θ

Y axis

        N - Wₓ = 0

        N = mg sin  θ

X axis

         fr = m a

the friction force has the expression

         fr = μ N

         fr = μ mg sin θ

we look for the job

         W = - μ mg sin θ  x

where x is the distance along the slope

       

we substitute in 1

         -μ mg sin θ x = mg h - ½ m v²

let's use trigonometry to find the distance x

        tan 30 = h / x

        x = h / tan 30

we substitute

          -   \mu \ mg \ sin \theta \  \frac{h}{tan 30} \ x = m gh - ½ m v²

we use  

          tan 30 = sin30 / cos30

         

          v² = 2g h + 2 μ g h cos 30

          v = \sqrt{ 2gh \ (1+ cos 30}

let's calculate

          v = \sqrt{ 2 \ 9.8 \ 4 \ (1 + 0.05 \ cos \ 30)}

          v = 9.04 m / s

4 0
3 years ago
Select all that apply. Which of the following would increase the conductivity of a connecting wire?
lord [1]
What are your choices 

4 0
3 years ago
The answer please to this and how it’s urgent
oksano4ka [1.4K]

Answer:

rA = 9 i + 9 j

rB = 12 i - 9 j

rB - rA = 3 i - 18 j

so distance in between them

= √[3×3 + 18 × 18 )

= √(9+324)

= √333

= 18.3 m

6 0
3 years ago
Help please! this is science :)
SSSSS [86.1K]

Answer: Answer is B

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