All categories

3 years ago

What is the average velocity of the particle from rest to 15 seconds?

Physics

2 answers:

Hitman42 [59]3 years ago

5 0

Displacement/Time = 21m / 15s .

That's choice-D .

sdas [7]3 years ago

4 0

Answer : The correct option is, (D) 1.4 meters/second

Solution :

Average velocity : It is defined as the displacement per unit time.

Formula used for average velocity :

$v_{av}=\frac{d}{t}$

where,

$v_{av}$ = average velocity

d = displacement of the particle

t = time taken

Now put all the given values in the above formula, we get the average velocity of the particle.

$v_{av}=\frac{(21-0)m}{15s}=1.4m/s$

Therefore, the average velocity of the particle is, 1.4 meter/second.

You might be interested in

Scrie un eseu la tema:,,Rolul cîmpului magnetic al Pămîntului asupra omenirii

Savatey [412]

Answer:

AREN'T

URGENT

WHY

Explanation:

WHY

5 0

3 years ago

Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 2.88 kg and rotate with

Tanya [424]

Answer:

(a) $K_{small}=4839.3J$

(b) $K_{larger}=17406.4J$

Explanation:

Given data

The angular velocity of two cylinders ω=257 rad/s

The mass of the two cylinders m=2.88 kg

The radius of small cylinder r₁=0.319 m

The radius of larger cylinder r₂=0.605 m

For Part (a)

The rotational kinetic energy of the cylinder is given by:

$K=\frac{1}{2}Iw^2$

Where I is rotational of inertia of solid cylinder about its central axis.

$K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr^2)w^2$

Substitute the given values

$K_{small}=\frac{1}{4}(2.88kg)(0.319)^2(257rad/s)^2 \\K_{small}=4839.3J$

For Part (b)

$K=\frac{1}{2}Iw^2\\ K=\frac{1}{2}(1/2mr_{2}^2)w^2$

Substitute the given values

$K_{larger}=\frac{1}{4}mr_{2}^2w^2\\ K_{larger}=\frac{1}{4}(2.88kg)(0.605m)^2(257rad/s)^2\\ K_{larger}=17406.4J$

8 0

3 years ago

An astronaut is on the moon. He drops a hammer from a height of 3.2metres and it takes 2.0 seconds to reach the lunar landscape.

Anvisha [2.4K]

Answer:

1/6 m/s^2 ( about 1/6th gravity of Earth ( 9.81 m/s^2)

Explanation:

Displacement = yo + vo t - 1/2 a t^2

- 3.2 = 0 + 0 - 1/2 a(2.0)^2

- 3.2 = -2a

a = 3.2 / 2 = 1.6 m/s^2

6 0

2 years ago

Two pulses are moving along a string. One pulse is

raketka [301]

Answer:

The answer is the 3rd option!

6 0

2 years ago

Short Answer Questions:

Otrada [13]

According to Archimede's principle, a physical object experiences an upthrust due to a difference in pressure between upper and lower surfaces.

<h3>What is an upthrust?</h3>

An upthrust is also referred to as buoyancy and it can be defined as an upward force which is exerted by a fluid (liquid or gas), so as to oppose the weight of a partially or fully immersed physical object that is floating in it.

Based on scientific information, a physical object experiences an upthrust when it is immersed in a fluid due to a difference in height and pressure between upper (top) and lower (bottom) surfaces.

According to Archimede's principle, there is a higher pressure at the bottom of the physical object due to height, and a lower pressure at the top of the physical object.

Read more on upthrust here: brainly.com/question/24389514

#SPJ1

4 0

2 years ago