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Julli [10]
3 years ago
10

What is the average velocity of the particle from rest to 15 seconds?

Physics
2 answers:
Hitman42 [59]3 years ago
5 0
Displacement/Time = 21m / 15s .

That's choice-D .
sdas [7]3 years ago
4 0

Answer : The correct option is, (D) 1.4 meters/second

Solution :

Average velocity : It is defined as the displacement per unit time.

Formula used for average velocity :

v_{av}=\frac{d}{t}

where,

v_{av} = average velocity

d = displacement of the particle

t = time taken

Now put all the given values in the above formula, we get the average velocity of the particle.

v_{av}=\frac{(21-0)m}{15s}=1.4m/s

Therefore, the average velocity of the particle is, 1.4 meter/second.

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Answer:

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Explanation:

It is given that,

The dimension of rectangular surface is 2.80 cm by 3.15 cm. The area of rectangular surface is, A=8.82\ cm^2=0.000882\ m^2

Angle between the uniform magnetic field and the horizontal, \theta=31

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Let B is the magnitude of magnetic field in which the rectangular surface is placed. It is given by :

\phi=BA\ cos\theta

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Here, \theta=90-31=59^{\circ}

B=\dfrac{\phi}{A\ cos\theta}

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