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hammer [34]
3 years ago
6

What are the metal things on the side o the road called

Chemistry
2 answers:
Lesechka [4]3 years ago
6 0
From what I know it's called traffic barrier
elena55 [62]3 years ago
5 0
They are called guard rails
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Which group is likely to react with chlorine to form compounds in the form xcl?
Umnica [9.8K]
Group 1 elements since they have one outermost electron which they can give to chlorine which has 7 outermost electrons in order to form a stable compound.

Example 
Pottasium (K) + Chlorine (Cl) = Potassium Chloride (KCL)
4 0
3 years ago
Hiii pls help me to write out the ionic equation ​
emmasim [6.3K]

Answer:

<u>STEP I</u>

This is the balanced equation for the given reaction:-

2KOH_{(aq)} + H_2SO_4{}_{(aq)}   \rightarrow K_2SO_4{}_{(aq)} + 2H_2O_{(l)}

<u>STEP II</u>

The compounds marked with (aq) are soluble ionic compounds. They must be

broken into their respective ions.

see, in the equation KOH, H2SO4, and K2SO4 are marked with (aq).

On breaking them into their respective ions :-

  • 2KOH -> 2K+ + 2OH-
  • H2SO4 -> 2H+ + (SO4)2-
  • K2SO4 -> 2K+ + (SO4)2-

<u>STEP III</u>

Rewriting these in the form of equation

\underline{\pmb{2K^+} }+ 2OH^- + 2H^+ + \pmb{\underline{{SO_4{}^{2-}}} \: \rightarrow \:  \underline{\pmb{2K^+}}} + \underline{\pmb{SO_4{}^{2-}}} + 2H_2O

<u>STEP </u><u>IV</u>

Canceling spectator ions, the ions that appear the same on either side of the equation

<em>(note: in the above step the ions in bold have gotten canceled.)</em>

\boxed{ \mathfrak{ \red{ 2OH^-{}_{(aq)} + 2H^+{(aq.)} \rightarrow H_2O{}_{(l)}}}}

This is the net ionic equation.

____________________________

\\

\mathfrak{\underline{\green{ Why\: KOH \:has\:  been\: taken\: as\: aqueous ?}}}

  • KOH has been taken as aqueous because the question informs us that we have a solution of KOH. by solution it means that KOH has been dissolved in water before use.

[Alkali metal hydroxides are the only halides soluble in water ]

4 0
3 years ago
Calculate the percent by mass of carbon in CO2 (carbon dioxide). Please show all work.
anygoal [31]
%C= 12/12 + 2·16=0,273=27,3%.
6 0
3 years ago
A chemist measures the amount of chlorine gas produced during an experiment. She finds that of chlorine gas is produced. Calcula
Trava [24]

Answer:

0.779 moles.

Explanation:

Mass of chlorine/number of moles = molar mass of chlorine.

Molar mass of chlorine = (35.5*2)

= 71 g/mol.

Mass = 55.3 g of chlorine.

Number of moles = 55.3/71

= 0.779 moles.

8 0
3 years ago
if during the interaction of 36.5 g of hydrochloric acid with magnesium 137 kg of joules energy are released, how much energy wo
svetoff [14.1K]

Explanation:

ANSWER

The molarity =

molecularweight

density×purity×10

=

36.5

1.18×36.5×10

=11.8molar

7 0
3 years ago
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