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3 years ago

Chris races his Audi north down a road for 1000 meters in 20 seconds, what is his velocity?

Physics

2 answers:

liq [111]3 years ago

5 0

The answer is 1000/20. Or that’s what I’m guessing. Lol

masha68 [24]3 years ago

4 0

Answer:

I think it would be 50 I am not really sure

Explanation:

I think you would have to divid 1000 by 20 Again I'm not sure

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A long solenoid (diameter = 5.0 cm) is wound with 960 turns per meter of thin wire through which a current of 300 mA is maintain

Semenov [28]

Answer: The magnetic field B= 4.82×10^-4T

Explanation:

There are two sources of magnetic field; the magnetic field due to solenoid and magnetic field due to wire. Their sum will give the total magnetic field

The magnetic field due to solenoid is constant at any point while the magnetic field due to wire varies with 1/radius.

Since they are perpendicular to each other;

Using Pythagoras theorem

B^2 =(B1)^2+B2)^2

B1 is the magnetic field due to solenoid and B2 is the magnetic field due to wire

B1= (μNI1)/L

B2=μI2/2πr

Where N/L is the of turns per meter = 960m^-1

I1 is the current in the solenoid =300mA=0.3A

I2 is the current in the wire = 12A

r is the distance from the axis of solenoid = 2cm= 0.02m

μ is the magnetic constant= 4π×10^-7Tm/A

Magnetic field due to solenoid B1=(4π×10^-7×960×0.3)

B1= (3.6191×10^-4 )

Magnetic field due to wire

B2 = (4π×10^-7×12)/2π × 0.02

B2 = 1.2×10^-4

B^2 =( 3.16191×10^-4)^2 × (1.2×10^-4)^2

B=3.8×10^-4T

Therefore the magnetic field is 0.38mT

5 0

3 years ago

A very loud train whistle has an acoustic power output of 100 W. If the sound energy spreads out spherically, what is the intens

valentina_108 [34]

Answer

given,

Power output of loud train = 100 W

Distance of intensity level from train= 100 m

I₀ = 10⁻¹² W/m²

Intensity of sound = ?

we know,

$I = \dfrac{P}{Area}$

$I = \dfrac{P}{4\pi r^2}$

$I = \dfrac{100}{4\pi 100^2}$

$I =7.957\times 10^{-4}\ W/m^2$

Intensity level

= $10 log(\dfrac{I}{I_0})$

= $10 log(\dfrac{7.975\times 10^{-4}}{10^{-12}})$

= $10 \times 8.900$

= 89 dB

7 0

3 years ago

What speed should a satellite of mass 4,900 kg moving around

Rudiy27

Based on the calculations, the speed required for this satellite to stay in orbit is equal to 1.8 × 10³ m/s.

Given the following data:

Gravitational constant = 6.67 × 10⁻¹¹ m/kg²

Mass of Moon = 7.36 × 10²² kg

Distance, r = 4.2 × 10⁶ m.

<h3>How to determine the speed of this satellite?</h3>

In order to determine the speed of this satellite to stay in orbit, the centripetal force acting on it must be sufficient to change its direction.

This ultimately implies that, the centripetal force must be equal to the gravitational force as shown below:

Fc = Fg

mv²/r = GmM/r²

Where:

m is the mass of the satellite.

M is mass of the Moon.

Making v the subject of formula, we have;

v = √(GM/r)

Substituting the given parameters into the formula, we have;

v = √(6.67 × 10⁻¹¹ × 7.36 × 10²²/4.2 × 10⁶)

v = √(1,168,838.095)

v = 1,081.13 m/s.

Speed, v = 1.8 × 10³ m/s.

Read more on speed here: brainly.com/question/20162935

#SPJ1

8 0

2 years ago

Which example nest represents balanced forces ???

n200080 [17]

Answer:

an elevator stopped on the third floor a basketball shot into a hoop a sled sliding down a snowy hill a tow truck pulling a car out of a ditch

5 0

2 years ago

Question number 8 Plz help

Dennis_Churaev [7]

To me, that sounds like the "Law of Conservation of Energy".

5 0

3 years ago