Answer:
19080667.0818 m/s
0.637294 m
Explanation:
m = Mass of deuterons =
v = Velocity
K = Kinetic energy = 3.8 MeV
d = Diameter
B = Magnetic field = 1.25 T
q = Charge of electron =
t = Time = 1 s
i = Current = 350 μA
Kinetic energy is given by
The speed of the deuterons when they exit is 19080667.0818 m/s
In this system the centripetal and magnetic force will balance each other
The diameter is 0.637294 m
Current is given by
The number of deuterons is
Answer:
Magnetic field = 0.534 T
Explanation:
The solving is on the attach document.
Answer:
b) Betelgeuse would be times brighter than Sirius
c) Since Betelgeuse brightness from Earth compared to the Sun is the statement saying that it would be like a second Sun is incorrect
Explanation:
The start brightness is related to it luminosity thought the following equation:
(1)
where is the brightness,
is the star luminosity and
, the distance from the star to the point where the brightness is calculated (measured). Thus:
b) and
where
is the Sun luminosity (
) but we don't need to know this value for solving the problem.
is light years.
Finding the ratio between the two brightness we get:
c) we can do the same as in b) but we need to know the distance from the Sun to the Earth, which is . Then
Notice that since the star luminosities are given with respect to the Sun luminosity we don't need to use any value a simple states the Sun luminosity as the unit, i.e 1. From this result, it is clear that when Betelgeuse explodes it won't be like having a second Sun, it brightness will be 5 orders of magnitude smaller that our Sun brightness.