The answer is 64.907 amu.
The atomic mass of an element is the average of the atomic masses of its isotopes. The relative abundance of isotopes must be taken into consideration, therefore:
atomic mass of copper = atomic mass of isotope 1 * abundance 1 + atomic mass of isotope 2 * abundance 2
We know:
atomic mass of copper = 63.546 amu
The atomic mass of isotope 1 is: 62.939 amu
The abundance of isotope 1 is: 69.17% = 0.6917
The atomic mass of isotope 1 is: x
The abundance of isotope 2: 100% - 69.17% = 30.83% = 0.3083
Thus:
63.546 amu = 62.939 amu * 0.6917 + x * 0.3083
63.546 <span>amu = 43.535 amu + 0.3083x
</span>⇒ 63.546 amu - 43.535 amu = 0.3083x
⇒ 20.011 amu = 0.3083x
⇒ x = 20.011 amu ÷ 0.3083 = 64.907 amu
It’s the elements that weigh the most are created when the events!
u on canvas?
Answer:
![AU^{3+} : [Rn] 5f^3](https://tex.z-dn.net/?f=AU%5E%7B3%2B%7D%20%3A%20%5BRn%5D%205f%5E3)
Explanation:
Writing electronic configuration of any element you should know atomic number of that element ,
and also electrons are filling according to their energy level and first electron is filled in the lower energy orbital
and it follows n+1 rule if n+1 is same for two orbital electron will go first in the lowest value of n.
writing electronic configuration of ion can be done like first for their neutral atom and then add or remove electron it will make things easy because there are also some eception case their you may do wrong.
![AU : [Rn] 5f^3 6d^1 7s^2](https://tex.z-dn.net/?f=AU%20%3A%20%5BRn%5D%205f%5E3%206d%5E1%207s%5E2)
remove three electron from outer most shell of AU
mass of N₂ = 25.76 g
mass of O₂ = 58.88 g
Explanation:
Nitrogen (N₂) will react with oxygen (O₂) to form trinitrogen tetroxide (N₂O₄).
N₂ + 2 O₂ → N₂O₄
number of moles = mass / molecular weight
number of moles of N₂O₄ = 85 / 92 = 0.92 moles
Knowing the chemical reaction we devise the following reasoning:
if 1 moles of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄
then X moles of N₂ react with Y moles of O₂ to produce 0.92 moles of N₂O₄
X = (1 × 0.92) / 1 = 0.92 moles of N₂
Y = (2 × 0.92) / 1 = 1.84 moles of O₂
mass = number of moles × molecular weight
mass of N₂ = 0.92 × 28 = 25.76 g
mass of O₂ = 1.84 × 32 = 58.88 g
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moles
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Bromine vs Chlorine | Br vs Cl
Halogens are group VII elements in the periodic table, and all are electronegative elements and have the capability to produce -1 anions.
Bromine
Bromine is denoted by the symbol Br. This is in the 4th period of the periodic table between chlorine and iodine halogens. Its electronic configuration is [Ar] 4s2 3d10 4p5. The atomic number of bromine is 35. Its atomic mass is 79.904. Bromine staChlorine is an element in the periodic table which is denoted by Cl. It is a halogen (17th group) in the 3rd period of the periodic table. The atomic number of chlorine is 17; thus, it has seventeen protons and seventeen electrons. Its electron configuration is written as 1s2 2s2 2p6 3s2 3p5. Since the p sub level should have 6 electrons to obtain the Argon, noble gas electron configuration, chlorine has the ability to attract an electron. ys as a red-brown color liquid at room temperature.
