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Wewaii [24]
3 years ago
8

A caterpillar crawls 20 feet in 5 minutes. What is the caterpillars crawling speed?

Physics
1 answer:
Pavel [41]3 years ago
6 0
The equation is
s= d/t

In this case you would have to write it out as:
s= 20/5
Speed = 4
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A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c
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Answer:

66.5N

Explanation:

F = kx

Where F = force

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x = compression

Given

K = 950N/m

x = 7.0cm

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Answer : The final temperature of gas is 266.12 K

Explanation :

According to the Joule-Thomson experiment, it states that when a gas is expanded adiabatically from higher pressure region to lower pressure region, the change in temperature with respect to change in pressure at constant enthalpy is known as Joule-Thomson coefficient.

The formula will be:

\mu_{J,T}=(\frac{dT}{dP})_H

or,

\mu_{J,T}=(\frac{dT}{dP})_H\approx \frac{\Delta T}{\Delta P}

As per question the formula will be:

\mu_{J,T}=\frac{T_2-T_1}{P_2-P_1}   .........(1)

where,

\mu_{J,T} = Joule-Thomson coefficient of the gas = 0.13K/atm

T_1 = initial temperature = 19.0^oC=273+19.0=292.0K

T_2 = final temperature = ?

P_1 = initial pressure = 200.0 atm

P_2 = final pressure = 0.95 atm

Now put all the given values in the above equation 1, we get:

0.13K/atm=\frac{T_2-292.0K}{(0.95-200.0)atm}

T_2=266.12K

Therefore, the final temperature of gas is 266.12 K

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