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3 years ago

Which of the objects below has the greatest acceleration? *

Physics

1 answer:

lesya692 [45]3 years ago

8 0

$\\ \bull\sf\dashrightarrow F=ma$

$\\ \bull\sf\dashrightarrow a=\dfrac{F}{m}$

Now

$\\ \bull\sf\dashrightarrow a\propto\dfrac{1}{m}$

$\\ \bull\sf\dashrightarrow a\propto F$

Lower mass=Higher acceleration
Lower Force=Lower Acceleration

Option B has lowest mass and highest force hence its correct

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A 0.111 kg hockey puck moving at 55 m/s is caught by a 80. kg goalie at rest. with what speed does the goalie slide on the frict

madreJ [45]

Answer:

0.076 m/s

Explanation:

Momentum is conserved:

m v = (m + M) V

(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V

V = 0.076 m/s

After catching the puck, the goalie slides at 0.076 m/s.

8 0

3 years ago

The maximum oxygen uptake is known as the

grandymaker [24]

<span>The maximum oxygen uptake is known as the VO max.</span>

3 0

3 years ago

A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collisi

ra1l [238]

Explanation:

Momentum = mass × speed

p = (30 kg) (3 m/s)

p = 90 kg m/s

7 0

3 years ago

A physicist makes a cup of instant coffee and notices that, as the coffee cools, its level drops 3.00 mm in the glass cup. Show

Lady bird [3.3K]

Answer:

change in height is 1.664 mm

Explanation:

Given data

drops = 3.00 mm

diameter = 5.00 cm = 0.05 mm

decrease = 350 cm^3

temperature = 95°C to 44.0°C

to find out

the decrease in millimeters in level

solution

we will calculate here change in volume so we can find how much level is decrease

change in volume = β v change in temp ...............1

here change in volume = area× height

so = $\pi$ /4 × d² h

so we can say change in volume = $\pi$ /4 × d² × change in height .......2

so from equation 1 and 2 we calculate change in height

( β(w) -β(g) )× v× change in temp = $\pi$ /4 × d² × change in height

change in height = 4 × ( β(w) -β(g) ) v× change in temp / $\pi$ /4 × d²

put all value here

change in height = 4 × ( 210 - 27 )(350 ) $10^{-6}$ × (95-44) / $\pi$ /4 × 0.05²

change in height is 1.664 mm

5 0

3 years ago

Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20Â°C. Container A is rigid. Container B has a 100 cm^2 pis

Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

Final Temperature of the gas in A will b GREATER than the temperature in B

Diagram of both processes on a single PV has been uploaded below,

Initial pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) / 0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial pressures in containers A and B is 3039.87 J/liters

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

Also work done = P( V₂ - V₁ )

so we substitute

375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

7 0

3 years ago