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Bond [772]
4 years ago
12

If a light ray is traveling from an object(clear plastic) into the air, and the refractive index for air is 1.00, how can the re

fractive index for clear plastic be calculated
Physics
1 answer:
mr Goodwill [35]4 years ago
3 0

You can use Snell's Law that relates the angles of the ray in the clear plastic and in the air to the ratio of their refraction indexes (n):

\frac{n_{plastic}}{n_{air}} =\frac{\sin\theta_{air}}{\sin\theta_{plastic}}

If you measure the two angles by experiment, then you can calculate the index of refraction of the clear plastic:

n_{plastic} =n_{air}\cdot\frac{\sin\theta_{air}}{\sin\theta_{plastic}}=1.0\cdot\frac{\sin\theta_{air}}{\sin\theta_{plastic}}

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A wheel of radius 0.23 m, which is moving initially at 25.0 m/s, rolls to a stop in 246.0 m. The wheel's rotational inertia is 0
Digiron [165]

Answer: -1.27 m/s^2

Explanation:

a = - V^2 / 2x

a = -(25^2) / 2 x (246) = 1.27 m/ s^2

Therefore the linear acceleration of the wheel is - 1.27 m/s^2

8 0
3 years ago
Steve tunes an old-fashioned radio that has an antenna made from a 3.0-cm-long solenoid with a cross-sectional area of 0.50 cm2
sukhopar [10]

Answer:

L = 1.88\times10^-^4 H

Explanation:

It is given that,

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Number of turns in the coil, N = 300

inductance of the coil is

L=\dfrac{\mu_oN^2A}{l}

L=\dfrac{4\pi\times 10^{-7}\times (300)^2\times 5\times 10^{-5}}{0.03}\\L = 1.88\times10^-^4 H

So, the inductance of the coil is 1.88× 10⁻⁴H

5 0
3 years ago
What effort force will be required to lift the 20 N object using the pulley above?
Umnica [9.8K]

Answer:

I think it is 5N.

Explanation:

4 0
3 years ago
What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force i
CaHeK987 [17]

Answer:

The friction coefficient's minimum value will be "0.173".

Explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒ F_{net}=ma

           =5\times 1.7

           =8.5 \ N

(b)

For m₃,

⇒ ma=\mu m_3 g

Or,

⇒    \mu=\frac{a}{g}

          =\frac{1.7}{9.8}

          =0.173

5 0
3 years ago
What is the princple behind electric generator
Liula [17]
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4 0
4 years ago
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