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3 years ago

5. What particle is located outside an atom's nucleus?

Chemistry

1 answer:

coldgirl [10]3 years ago

5 0

Answer:

Explanation:

Nucleons include protons and neutrons. All the positive charge of an atom is contained in the nucleus, and originates from the protons. Neutrons are neutrally-charged. Electrons, which are negatively-charged, are located outside of the nucleus.

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What is unique about the size and location of this exoplanet?

swat32

Answer:

It is the smallest planet found in the habitable zone.

Explanation:

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3 years ago

C(S)+O2(g)-->CO2(g)

soldi70 [24.7K]

Answer: The correct answer is 1.18 g.

Explanation:

We are given a chemical equation:

$C(S)+O2(g)\rightarrow CO_2(g)$

We know that at STP conditions:

22.4L of volume is occupied by 1 mole of a gas.

So, 2.21L of carbon dioxide is occupied by = $\frac{1}{22.4L}\times 2.21L=0.0986mol$ of carbon dioxide gas.

By Stoichiometry of the above reaction:

1 mole of carbon dioxide gas is produced by 1 mole of carbon

So, 0.0986 moles of carbon dioxide is produced by = $\frac{1}{1}\times 0.0986=0.0986mol$ of carbon.

Now, to calculate the mass of carbon, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of carbon = 0.0986 mol

Molar mass of carbon = 12 g/mol

Putting values in above equation, we get:

$0.0986mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=1.18g$

Hence, the correct answer is 1.18 g.

3 0

3 years ago

Read 2 more answers

Find the number of moles of water that can be formed if you have 230 mol of hydrogen gas and 110 mol of oxygen gas

Verdich [7]

Answer:

220mol.

Explanation:

Water is H2O. Hydrogen gas is H2. Oxygen gas is O2. You have 220mol of O and 460mol of H. O is the limiting reactant. The ratio O:H2O is 1:1. 220*1=220

3 0

3 years ago

What is different between an onic bond and a covalent bond?

Dmitriy789 [7]

The answer to the question

6 0

3 years ago

Read 2 more answers

A newly discovered element, Z, has two naturally occurring isotopes. 90.3 percent of the sample is an isotope with a mass of 267

kirill115 [55]

Ok so, remember that the average atomic mass is what is seen on the periodic table. It is the average mass of all of the isotopes with their frequency taken into account. What you need to do is add the products of the masses and frequencies Just like this:

0.903*267.8 + 0.097*270.9
When you add it the result is what you are looking for

4 0

3 years ago