Answer:
Theoretical yield of C6H10 = 3.2 g.
Explanation:
Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.
Equation of the reaction
C6H11OH --> C6H10 + H2O
Moles of C6H11OH:
Molar mass of C6H110H = (12*6) + (1*12) + 16
= 100 g/mol
Mass of C6H10 = 3.8 g
number of moles = mass/molar mass
=3.8/100
= 0.038 mol.
Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.
Therefore, 0.038 moles of C6H10 was produced.
Mass of C6H10 = molar mass * number of moles
Molar mass of C6H10 = (12*6) + (1*10)
= 82 g/mol.
Mass = 82 * 0.038
= 3.116 g of C6H10.
Theoretical yield of C6H10 = 3.2 g
Answer:
<h3>F=132k.gm/s^2</h3>
Explanation:
<h3>F=m×a</h3><h3>f=22k.g×6m/s^2</h3><h3>f=132k.gm/s^2</h3>
The (II) is a roman numeral indicating the oxidation number of a transition metal. It is used when you refer to the element/compound by name but does not show up in the formula.
The graph will begin at 20 °C and have temperature on the y-axis and time on the x-axis. The line will be a downwards sloping one, until the value of temperature of the graph reaches 0 °C. There, it will become horizontal for a small amount of time, and then continue to slope downwards until the graph reaches -20 <span>°C.
The horizontal region is where the freezing of water will take place, and there is no temperature change that occurs when a state change is taking place. This is because the energy involved then is latent energy.</span>
