Answer:
0.625 c
Explanation:
Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.
In the context,
The relative speed of body 2 with respect to body 1 can be expressed as :

Speed of rocket 1 with respect to rocket 2 :



Therefore, the speed of rocket 1 according to an observer on rocket 2 is 0.625 c
Let the key is free falling, therefore from equation of motion
.
Take initial velocity, u=0, so
.

As velocity moves with constant velocity of 3.5 m/s, therefore we can use formula

From above substituting t,
.
Now substituting all the given values and g = 9.8 m/s^2, we get
.
Thus, the distance the boat was from the point of impact when the key was released is 10.60 m.
Answer:
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Answer:
x = 0.0734 m = 7.34 cm
Explanation:
First we shall calculate the area of the piston:

Now, we will calculate the force on the piston due to atmospheric pressure:

Now, for the compression of the spring we will use Hooke's Law as follows:

where,
k = spring constant = 3400 N/m
x = compression = ?
Therefore,
<u>x = 0.0734 m = 7.34 cm</u>
The x and y components of the velocity vector is 17.32 m/s and 10 m/s respectively.
<h3>
What is the x - component of the velocity?</h3>
The x-component of the ball's velocity is the velocity of the ball in the horizontal direction or x-axis.
The velocity of the ball in x-direction is calculated as follows;
Vx = V cosθ
where;
- Vx is the horizontal velocity of the ball
- V is the speed of the ball
- θ is the angle of inclination of the speed
Vx = (20 m/s) x (cos 30)
Vx = 17.32 m/s
The velocity of the ball in y-direction is calculated as follows;
Vy = V sinθ
where;
- Vy is the vertical velocity of the ball
- V is the speed of the ball
- θ is the angle of inclination of the speed
Vy = 20 m/s x sin(30)
Vy = 10 m/s
Learn more about x and y components of velocity here: brainly.com/question/18090230
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