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Ainat [17]
3 years ago
14

A mixture of sodium bicarbonate and ammonium bicarbonate is 75.9% bicarbonate by mass. what is the mass percent of sodium bicarb

onate in the mixture?
Chemistry
1 answer:
Lorico [155]3 years ago
8 0
Answer: 24.1%,  under below assumptions.

Justification:

The question is quite ambiguous, because one of the data is not clearly stated. It says that the mixture consists on two compounds:

- sodium bicarbonate, and
- ammonium bicarbonate

.After, it says that it is 75.9 % bicarbonate, but it does not specify which bicarbonate, it might be the sodium bicarbonate or the ammonium bicarbonate. It is apparent that you omitted that information by error.

Given that later, the question is <span>what the mass percent of sodium bicarbonate is in the mixture, it is supposed that the 75.9% content is of ammonium bicarbonate.

With that said, you can calculate the mass percent of sodium bicarbonate, because there are only two compounds and so you know that both add up the 100% of the mixture.

In formulas:

100% = %m/m sodium bicarbonate + %m/m ammonium bicarbonate = 100%

=> % m/m sodium bicarbonate = 100% - % m/s ammonium bicarbonate

=> % sodium bicarbonate = 100% - 75.9% = 24.1%

Answer: 24.1%
</span>
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4NH3+5O2=4NO+6H20 if 32.5 grams of NH3 react with enough oxygen, how many grams of water should form?
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51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

<h3>How to find the Number of moles ?</h3>

To calculate the number of moles use the formula

Number of moles = \frac{\text{Given Mass}}{\text{Molar Mass}}

                              = \frac{32.5}{17}

                              = 1.9 mol

4NH₃ + 5O₂ → 4NO + 6H₂O

4 mol of NH₃ react with oxygen to given 6 mole of water.

So 1.9 mol of NH₃ produces = \frac{1.9}{4}\times 6

                                              = 2.85 mol of water

Mass of water = Molar Mass of water × Number of moles of water

                        = 18 × 2.85

                        = 51.3 gram

Thus from the above conclusion we can say that 51.3 gram of water should form if 32.5 g of NH₃ react with enough oxygen.

Learn more about the Moles here: brainly.com/question/15356425

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There are eight elements in the second row (lithium to neon) of the periodic table.
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