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3 years ago

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Which of the following quantities are unknown? initial separation of the particles final separation of the particles initial spe

ed of the proton initial speed of the alpha particle final speed of the proton final speed of the alpha particle mass of the proton mass of the alpha particle charge of the proton charge of the alpha particle Enter the letters of all the correct answers in alphabetical order. Do not use commas. For instance, if A, C, and D are unknowns, enter ACD.

1 answer:

tino4ka555 [31]3 years ago

7 0

ALL of the quantities are unknown, because you haven't bothered to tell us anything that's known.

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A ball is projected at an angle of 53º. If the initial velocity is 48 meters/second, what is the vertical component of the veloc

solong [7]

Answer: B

Explanation:

The vertical component of a vector such as velocity is the magnitude of the vector multiplied by the sine of the angle.

$V_y=48*sin(53)=38.3m/s$

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3 years ago

What is the free-fall acceleration at the surface of the jupiter?

Rufina [12.5K]

Answer:

24.79 m/s2

Explanation:

Let us assume that there is an object with a mass of 'm' on the

Jupiter. Jupiter will attract this object:

$mg_j=G\frac{mM_j}{r_j^{2} }$

$g_j=G\frac{M_j}{r_j^{2} }$

$g_j=6.67*10^{-11} \frac{1.9*10^{27} }{71492000^{2} }$

$g_j=24.79m/s^{2}$

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4 years ago

g determine what frequency is required of a source powering a 100 uf capacitor a 500 ohm resistor and a s50 mH inductor in serie

polet [3.4K]

Answer: $71.16\ Hz$

Explanation:

Given

Capacitance $C=100\ \mu F$

Resistance $R=500\ \Omega$

Inductance $L=50\ mH$

In LCR circuit, current is maximum at resonance frequency i.e.

$X_L=X_C\ \text{and}\ \omega_o=\dfrac{1}{\sqrt{LC}}$

Insert the values

$\Rightarrow \omega_o=\dfrac{1}{\sqrt{50\times 10^{-3}\times 100\times 10^{-6}}}\\\\\Rightarrow \omega_o=\dfrac{1}{\sqrt{5}\times 10^{-3}}\\\\\Rightarrow \omega_o=0.447\times 10^{3}$

Also, frequency is given by

$\Rightarrow 2\pi f=\omega_o\\\\\Rightarrow f=\frac{\omega_o}{2\pi}$

$\Rightarrow f=\dfrac{1}{2\pi}\times 0.447\times 10^3\\\\\Rightarrow f=71.16\ Hz$

8 0

3 years ago

Two weights are connected by a very light cord that passes over an 80.0Nfrictionless pulley of radius 0.300m. The pulley is a so

Citrus2011 [14]

Answer:

The force does the ceiling exert on the hook is 269.59 N

Explanation:

Applying the second Newton law:

F = m*a

From the attached diagram, the net force in object 1 is:

$m_{1} a=T_{1} -W_{1}$

In object 2:

$m_{2} a=W_{2} -T_{2}$

Adding the two equations:

$m_{2} a+m_{1} a=T_{1} -W_{1} +W_{2} -T_{2} \\m_{1} =\frac{W_{1} }{g} \\m_{2} =\frac{W_{2} }{g} \\Replacing\\T_{2}-T_{1}=W_{2} -W_{1} -(\frac{W_{1} }{g} +\frac{W_{2} }{g} )a$ (eq. 1)

The torque:

$\tau =I\alpha$

Where

I = moment of inertia

α = angular acceleration

If the linear acceleration is

$a=r\alpha \\\alpha =\frac{a}{r} \\I=\frac{1}{2} mr^{2} \\\tau =\frac{mra}{2}$

Torque due the tension is equal:

$\tau =r(T_{2} -T_{1} )$

Substituting torque, mass, in equation 1, the expression respect the acceleration is:

$a=\frac{g*(W_{2}-W_{1})}{W_{1}+W_{2} +\frac{W}{2} }$

Where

W₁ = 75 N

W₂ = 125 N

W = 80 N

$a=\frac{9.8*(125-75)}{75+125+\frac{80}{2} } =2.04m/s^{2}$

The net force is:

$F_{n} =F-W-T_{1} -T_{2}\\0=F-W-W_{1} (\frac{a}{g} +1)-W_{2} (1-\frac{a}{g})\\F=W+W_{1} +W_{2} +\frac{a}{g} (W_{1} -W_{2} )\\F=80+75+125+\frac{2.04}{9.8} (75-125)\\F=269.59N$

4 0

3 years ago

The wasted energy in processing food is “lost” to ____.

storchak [24]

I think its maybe light energy

8 0

3 years ago

Read 2 more answers