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Inga [223]
3 years ago
5

Two technicians are discussing a fuel gauge on a General Motors vehicle. Technician A says that if the ground wire's connection

to the fuel tank sending unit becomes rusty or corroded, the fuel gauge will read lower than normal. Technician B says that if the power lead to the fuel tank sending unit is disconnected from the tank unit and grounded (ignition on), the fuel gauge should go to empty. Which technician is correct?
a. Technician A only
b. Technician B only
c. Both Technicians A and B
d. Neither Technician A nor B
Physics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

b. Technician B only

Explanation:

There is a float connected to the variable resistor in a fuel tank unit. The resistance of the variable resistor also changes as the fuel level changes. The tank unit's resistance changes, the dash mount gauge also changes and available on driver's display.  

If the tank transmitter is disconnected, the operation will not take place and the resistance change will not be transmitted to the dash unit. The needle will therefore remain the empty one at all times.Even after being rusty, the ground wire connection to the fuel tank will be able to conduct. Hence Technician B   is correct and Technician A is incorrect.

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Answer:

Stars are born within the clouds of dust and scattered throughout most galaxies. Deep within these clouds, turbulence creates knots with enough mass to cause the gas and dust to collapse under its own gravitational force.

4 0
3 years ago
Which statement about an atom is correct?
Alexus [3.1K]

Answer:

\boxed{ \sf{The \: electron \: has \: a \: negative \: charge \: and \: is \: found \: outside \: of \: the \: nucleus}}

Option A is correct

Explanation:

Let's check the options:

A: The electron has a negative charge and is found outside of the nucleus.

\mapsto{} Yeah! It's TRUE . An electron is a <u>negatively</u><u> </u><u>charged</u><u> </u><u>particle</u><u> </u><u>and</u><u> </u><u>is</u><u> </u><u>located</u><u> </u><u>outside</u><u> </u><u>the</u><u> </u><u>nucleus</u><u> </u><u>of</u><u> </u><u>an</u><u> </u><u>atom.</u>

B : The neutron has a negative charge and is found in the nucleus.

\mapsto{}No! It's FALSE . A neutron carries <u>no </u><u>charge</u>. i.e it is a neutral particle and found inside the nucleus.

C : The proton has no charge and is found in the nucleus.

\mapsto{}No! It's FALSE.A proton is a <u>positively</u><u> </u><u>charged</u><u> </u><u>particle</u> present inside nucleus of an atom.

D : The neutron has no charge and is found outside of the nucleus.

\mapsto{} I agree that the neutron has no charge. But it is found <u>inside</u> the nucleus not outside . So, this statement is FALSE .

Hence, we found our answer! :D

A. The electron has a negative charge and is found outside of the nucleus is the correct statement about an atom.

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
3 years ago
Iron combines with oxygen and water from the air to form rust. If an iron nail were
rusak2 [61]

Answer:

When iron rusts - in the presence of moisture and oxygen - iron-oxide is formed. Iron oxide is nothing but a compound of iron and oxygen. There is an increase in the mass of the iron equal to the mass of oxygen that has gone into forming the rust.

<em>hope it helps:)</em>

8 0
3 years ago
How is light used to make other form of transportations safer
Rzqust [24]
It makes it easier to see in dark places
7 0
3 years ago
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that ha
jasenka [17]

Explanation:

It is given that,

Mass of an object, m=4\times 10^5\ kg

(a) Time period of oscillation, T = 2.4 s

The formula for the time period of spring is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

Where

k is the force constant

k=\dfrac{4\pi ^2 m}{T^2}

k=\dfrac{4\pi ^2 \times 4\times 10^5}{(2.4)^2}

k=2.74\times 10^6\ N/m

(b) Displacement in the spring, x = 2.2 m

Energy stored in the spring is given by :

U=\dfrac{1}{2}kx^2

U=\dfrac{1}{2}\times 2.74\times 10^6\ N/m\times (2.2\ m)^2

U=6.63\times 10^6\ J

Hence, this is the required solution.

7 0
3 years ago
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