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liraira [26]
4 years ago
5

Hot water at an average temperature of 88°C and an average velocity of 0.4 m/s is flowing through a 5-m section of a thin-walled

hot-water pipe that has an outer diameter of 2.5 cm. The pipe passes through the center of a 14-cm-thick wall filled with fiberglass insulation (k = 0.035 W/m·K). The surfaces of the wall are at 18°C.a. Determine the rate of heat transfer from the pipe to the air in the rooms. b. Determine the temperature drop of the hot water as it flows through the 5-m-long section of the wall where the steady rate of heat transfer from the pipe is 39.153 W. For water, use density (rho) 1000 kg/m^3 and specific capacity of heat (cp) =4180 J/kg.°C.

Engineering
1 answer:
SIZIF [17.4K]4 years ago
4 0

Answer:

a) The rate of heat transfer will be 19.58 Watts.

b) The temperature drop of the hot water will be 0.024 Degree Celcius.

Explanation:

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It is desired to produce and aligned carbon fiber-epoxy matrix composite having a longitudinal tensile strength of 610 MPa. Calc
julia-pushkina [17]

Answer:

volume fraction of fibers is 0.4

Explanation:

Given that for the aligned carbon fiber-epoxy matrix composite:

Diameter (D) = 0.029 mm

Length (L) = 2.3 mm

Tensile strength (\sigma_{cd}) = 610 MPa

fracture strength (\sigma_f) = 5300 MPa

matrix stress (\sigma_m) =  17.3 MPa

fiber-matrix bond strength (\tau_c) = 19 MPa

The critical length is given as:

L_C=\sigma_f(\frac{D}{2\tau_c} )=5300*10^6(\frac{0.029*10^{-3}}{19*10^6} )=8.1*10^{-3}=8.1mm

Since the critical length is greater than the length, the aligned carbon fiber-epoxy matrix composite can be produced.

The longitudinal strength is given by:

\sigma_{cd}=\frac{L*\tau_c}{D} .V_f+\sigma_m(1-V_f)

making Vf the subject of the formula:

V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}

Vf is the volume fraction of fibers.

Therefore:

V_f=\frac{\sigma_{cd}-\sigma_m}{\frac{L*\tau_c}{D} -\sigma_m}=\frac{610*10^6-17.3*10^6}{\frac{2.3*10^{-3}*19*10^6}{0.029*10^{-3}}-17.3*10^6} } =0.4

volume fraction of fibers is 0.4

8 0
3 years ago
Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part
ra1l [238]

Answer:

h1 = 290.16kj/kg

P = 1.2311

Prandil expression at 8

P=p1/p7×pr

=8(1.2311)

=9.85

Enthalpy state at 8 corresponding to 9.85

h1 = 526.13kj/kg

Now prandtl state at 9 that correspond to 1400k.

h9 = 1515.42kj/kg

Pr = 450.5

Prandtl expression at state 10

P= p10/p9×pr

=1/8(450.5)

=56.31

Enthalpy at state 10 corresponding to prandtl 56.31

h10 = 860.39kj/kg

At 520k

h11 = 523.63kj/kg

4 0
3 years ago
Select the correct answer.
babunello [35]

Answer:

The information he needs next is;

B. Volume of paint needed per unit area

Explanation:

The operation Andy wants to perform = To apply paint on the walls of the house

The information Andy knows = The area of all walls in the house

The total volume of paint needed = The total area of the walls × The volume of paint needed for each unit area

Therefore, the information required is the volume of paint needed per unit area.

3 0
3 years ago
Public transport is a generic term used to describe the family of transit services available to
Softa [21]

Answer:

true

Explanation:

it is used to describe the family of transit services available to residents of urban area

5 0
3 years ago
A multipurpose transformer has a secondary coil with several points at which a voltage can be extracted, giving outputs of 5.60,
Rudik [331]

Answer:

for 5.6V 9 turns, for 12.0V 19 turns, for 480V 755 turns

Explanation:

Vp/Vs= Np/Ns

Vp: Primary voltage

Vs: Secondary Voltage

Np: number of turns on primary side

Ns: number of turns on secondary side

for output 5.6V

140/5.6= 220/Ns

Ns= 8.8 or 9 Turns

for output 12.0V

140/12= 220/Ns

Ns= 18.9 or 19 turns

for output 480V

140/480= 220/Ns

Ns= 754.3 or 755 turns

4 0
4 years ago
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