Answer:
Explanation:
Given:
Tooth Number, N = 24
Diametral pitch pd = 12
pitch diameter, d = N/pd = 24/12 = 2in
circular pitch, pc = π/pd = 3.142/12 = 0.2618in
Addendum, a = 1/pd = 1/12 =0.08333in
Dedendum, b = 1.25/pd = 0.10417in
Tooth thickness, t = 0.5pc = 0,5 * 0.2618 = 0.1309in
Clearance, c = 0.25/pd = 0.25/12 = 0.02083in
The load is 17156 N.
<u>Explanation:</u>
First compute the flexural strength from:
σ = FL / π
= 3000 (40 10^-3) / π (5 10^-3)^3
σ = 305 10^6 N / m^2.
We can now determine the load using:
F = 2σd^3 / 3L
= 2(305 10^6) (15 10^-3)^3 / 3(40 10^-3)
F = 17156 N.
Answer:
coupling is in tension
Force = -244.81 N
Explanation:
Diameter of Hose ( D1 ) = 35 mm
Diameter of nozzle ( D2 ) = 25 mm
water gage pressure in hose = 510 kPa
stream leaving the nozzle is uniform
exit speed and pressure = 32 m/s and atmospheric
<u>Determine the force transmitted by the coupling between the nozzle and hose </u>
attached below is the remaining part of the detailed solution
Inlet velocity ( V1 ) = V2 ( D2/D1 )^2
= 32 ( 25 / 35 )^2
= 16.33 m/s
Answer:
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Explanation:
Answer:crane and engine I guess
Explanation: