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FinnZ [79.3K]
3 years ago
6

If the beam is made from wood having an allowable shear stress τallow = 390 psi , determine the maximum magnitude of p. set d =

4 in.

Physics
1 answer:
xenn [34]3 years ago
3 0

Answer:

19593.6 p

Explanation:

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B. Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
goblinko [34]

We have that the instantaneous velocity of the shuttlecock when it hits the ground is

V_{int}=\sqrt{U^2+19.6H}

From the question we are told

Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the

shuttlecock when it hits the ground? Show your work below.

Generally the equation for acceleration  is mathematically given as

a=v \frac{dv}{dx}\\\\\Therefore\\\\\2ah=v^2-u^2

Where

acceleration is still -9.81 m/s2,

Hence,

V^2-U^2=2(-9.81)*-H

Therefore

V_{int}=\sqrt{U^2+19.6H}

For more information on this visit

brainly.com/question/12319416?referrer=searchResults

7 0
2 years ago
I need help me with my question
lisov135 [29]

The tilt of the moon's axis does not allow for monthly alignment, so the lunar and solar eclipse do not happen every month.

<h3>How do the lunar and solar eclipse occur?</h3>
  • For the occurrence of lunar and solar eclipse, the sun, moon and the earth must remain in a plan and along a straight line.
  • When the earth appears in between the sun and the moon, lunar eclipse occurs.
  • When the moon appears in between the sun and the earth, solar eclipse occurs.
  • The moon and earth are rotating not only around the sun, but also around the black hole of Milky way galaxy.
  • So they are not present in a plan as well as in a straight line in every full moon and new moon time.

Thus, we can conclude that the option D is correct.

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4 0
2 years ago
What type of evidence is needed for a hypothesis to be supported or not supported?
NISA [10]

Answer:

Hypotheses must be testable, and once tested, they can be supported by evidence. If a statement is made that cannot be tested and disproved, then it is not a hypothesis.

8 0
2 years ago
A stone is projected from the ground with a velocity 14m/s one second later it clears a wall 2 m high. The angle of projection i
Eva8 [605]

Answer:

30 degrees

i can't put in my work on paper

6 0
3 years ago
Read 2 more answers
A 0.091-in-diameter electrical wire at 90°F is covered by 0.02-in-thick plastic insulation (k = 0.075 Btu/h·ft·°F). The wire is
olya-2409 [2.1K]

Answer:

The critical radius of the plastic insulation is 0.72 inches.

Explanation:

Given that,

Diameter = 0.091 in

Thickness = 0.02 in

Initial temperature = 90°F

Final temperature = 50°F

Heat transfer coefficient = 2.5 Btu/h.ft²°F

Material conductivity = 0.075 Btu/h.ft °F

We need to calculate the critical radius of the plastic insulation

Using formula of critical radius

r_{cr}=\dfrac{2K}{h}

Where, k = Material conductivity

h = Heat transfer coefficient

Put the value into the formula

r_{cr}=\dfrac{2\times0.075}{2.5}

r_{cr}=0.06\ ft

r_{cr}=0.72\ inches

Hence, The critical radius of the plastic insulation is 0.72 inches.

4 0
2 years ago
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