Answer:
H2O> NH3> CH4
Explanation:
According to valence shell electron pair repulsion theory (VSEPR), bond angles and repulsion of electron pairs depends on the nature of electron pairs on the central atom of the molecule. Lone pairs cause more repulsion (and distortion of bond angles) than bond pairs). Lone pair- lone pair repulsion is greater than lone pair bond pair repulsion.
Water contains two lone pairs on oxygen hence it experiences the greatest repulsion. Ammonia has only one lone pair on nitrogen hence there is lesser repulsion between lone pairs and bond pairs. Methane possess only bond pairs of electrons hence it has the least repulsion.
Empirical evidence is information acquired by observation or experimentation
Answer:
The correct answers are: <u>Each oxygen of carbonate ion has -2/3 or -0.67 charge.</u>
<u>Bond order of each carbon‑oxygen bond in the carbonate ion</u> = <u>1.33</u>
Explanation:
The carbonate ion (CO₃²⁻) is an organic compound, in which a carbon atom is covalently bonded to three oxygen atoms. The net formal charge on a carbonate ion is −2.
The carbonate ion is <u>resonance stabilized</u> and has three equivalent resonating structures, which exhibits that all the three carbon-oxygen bonds in a carbonate ion are equivalent.
In the resonance hybrid of carbonate ion,<u> the negative charge is equally delocalized on all the three oxygen atoms. </u>
<u>Thus, each bonded oxygen has -2/3 or -0.67 charge.</u>
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In a carbonate ion there is one double bond oxygen (C=O) and two single bonded oxygen (C-O). Bond order of 1 C=O is 2 and bond order of C-O is 1.
∴ <u>Bond order</u> = sum of all bond orders ÷ number of bonding groups = (2+1+1) ÷ 3 = <u>1.33</u>
That would be the compound Ba(NO3)2. The Barium ion has a charge of 2+ so there are 2 NO3- ions in the formula to produce a neutral compound.
Use this equation:
q = mc∆T
q is the heat energy your trying to find out
m is the mass of water (150g)
c is the specific heat capacity of water (4.18)
∆T is the temperature change (96.3-38.8)
so just multiply m c and ∆T to find q in joules
