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Vesnalui [34]
3 years ago
14

Suppose that you're facing a straight current-carrying conductor, and the current is flowing toward you. The lines of magnetic f

orce at any point in the magnetic field will act in:________
a. the same direction as the current.
b. a clockwise direction.
c. a counterclockwise direction.
d. the direction opposite to the current.
Physics
1 answer:
alekssr [168]3 years ago
8 0

Answer:c

Explanation:

When the direction of current is towards the observer then the magnetic field around it will be in the form of concentric circles and its direction will be anti-clockwise when viewed from the observer side.

Whenever current is flowing in a current-carrying conductor then the magnetic field is associated with it and direction of the magnetic field is given by right-hand thumb rule according to which if thumb represents the direction of current then wrapping of fingers will give the direction of the magnetic field                

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Answer:3.0hertz

Explanation:

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Answer: The focal length of the lens = 3.32 cm.

Explanation:

Lens formula : \dfrac1f=\dfrac1v-\dfrac1u    (i)

f= focal length , v=image distance , u =object distance.

magnification: m = \dfrac{v}{u}   (ii )

Given: v= -12.8 cm , m =2.85

Put values in (ii), we get

2.85=\dfrac{-12.8}{u}\\\\\Rightarrow\ u=\dfrac{-12.8}{2.85}\\\\\Rightarrow\ u=-4.49\  cm

substitute values of u , v in (i)

\dfrac1f=\dfrac1{-12.8}-\dfrac{1}{4.49}\\\\\Rightarrow\dfrac1f=-0.30084214922\\\\\Rightarrow\ f=\dfrac{-1}{-0.30084214922}\approx3.32\ cm

Hence, the focal length of the lens = 3.32 cm.

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3 years ago
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What are some model limitations?
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A ray of light incident in air strikes a rectangular glass block of refractive index 1.50, at an angle of incidence of 45°. Calc
balandron [24]

Answer:

Approximately 28^{\circ}.

Explanation:

The refractive index of the air n_{\text{air}} is approximately 1.00.

Let n_\text{glass} denote the refractive index of the glass block, and let \theta _{\text{glass}} denote the angle of refraction in the glass. Let \theta_\text{air} denote the angle at which the light enters the glass block from the air.

By Snell's Law:

n_{\text{glass}} \, \sin(\theta_{\text{glass}}) = n_{\text{air}} \, \sin(\theta_{\text{air}}).

Rearrange the Snell's Law equation to obtain:

\begin{aligned} \sin(\theta_{\text{glass}}) &= \frac{n_{\text{air}} \, \sin(\theta_{\text{air}})}{n_{\text{glass}}} \\ &= \frac{(1.00)\, (\sin(45^{\circ}))}{1.50} \\ &\approx 0.471\end{aligned}.

Hence:

\begin{aligned} \theta_{\text{glass}} &= \arcsin (0.471) \approx 28^{\circ}\end{aligned}.

In other words, the angle of refraction in the glass would be approximately 28^{\circ}.

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