I believe that it most likely would be C,
(a)
The formula is:
∑ F = Weight + T = mass * acceleration
as the elevator and lamp are moving downward, I choose downward forces to be
positive.
Weight is pulling down = +(9.8 * mass)
Tension is pulling up, so T = -63
Acceleration is upward = -1.7 m/s^2
(9.8 * mass) + -63 = mass * -1.7
Add +63 to both sides
Add (mass * 1.7) to both sides
(9.8 * mass) + (mass * 1.7) = 63
11.5 * mass = 63
mass = 63 / 11.5
Mass = 5.48 kg
(b)
Since the elevator and lamp are going upward, I choose upward forces to be
positive.
Weight is pulling down = -(9.8 * 5.48) = -53.70
Acceleration is upward, so acceleration = +1.7
-53.70 + T = 5.48 * 1.7
T = 53.70 + 9.316 = approx 63 N
The Tension is still the same - 63 N since the same mass, 5.48 kg, is being accelerated
upward at the same rate of 1.7 m/s^2
Answer:
True.
Explanation:
A more practical use of constellations was for agriculture. Before calendars were invented farmers relied on the stars to determine when to sow and harvest their crops. Constellations made the patterns of the stars easy to remember. ... Constellations allowed farmers to plan ahead.
The source of the sound it moving closer to you because the wavelength is shortened. The shorter the wavelength, the higher the frequency, the higher the pitch
Answer:
Yes.
Explanation:
Notice how mass and force affect acceleration. The <em><u>acceleration of an object increases with increased force, decreases with increased mass, and is in the same direction as the force.</u></em>
When an external force acts on an object, the change in the object's motion will be directly related to its mass. This change in motion, known as acceleration, depends upon the object's mass and the strength of the external force.
Newton's second law shows that there is a direct relationship between force and acceleration. The greater the mass of an object, the less it will accelerate when a given force is applied. For example, <em><u>doubling the mass of an object results in only half as much acceleration for the same amount of force.</u></em>
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I hope this helps you!
