Answer:
Car B has a mass of 800 kg.
General Formulas and Concepts:
<u>Momentum</u>
Law of Conservation of Momentum:
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] m₁ = 1200 kg
[Given] v₁i = 10 m/s
[Solve] m₂
[Given] v₂i = 0 m/s
[Given] vf = 6 m/s
<u>Step 2: Solve for m₂</u>
- Substitute in variables [Law of Conservation of Momentum]: (1200 kg)(10 m/s) + m₂(0 m/s) = (1200 kg + m₂)(6 m/s)
- Multiply: 12000 kg · m/s = (1200 kg + m₂)(6 m/s)
- Isolate m₂ term: 2000 kg = 1200 kg + m₂
- Isolate m₂: 800 kg = m₂
Answer:
Explanation:
Given:
- mass of the first ball,
- initial velocity of the first ball,
- mass of the second ball,
- initial velocity of the second ball,
- Final velocity of the first ball,
<u>Using the law of conservation of linear momentum:</u>
where: final velocity of the second ball
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<u>Now the kinetic energy lost in the collision:</u>
Δ KE = (Sum of initial individual kinetic energy) - (Sum of individual final kinetic energy)
Answer:
Distance = 0.738 m
Explanation:
Solution:
<u>
First convert Km/h into m/s.</u>
75 km/h * 1000 m/km * 1 hr/3600 sec = 20.8333 m/s
<u>According to third equation of motion:
</u>
– = 2 * acceleration * distance
<em>
Vf= final velocity </em>
<em>Vi= initial velocity</em>
putting values in third equation of motion....
– = 2 * (-30 * 9.8) * distance
note:
negative sign is due to deceleration
Distance = 0.738 m
Interesting ...
gravity can be considered as *constant* acceleration, then you have:
h = v0*t + 1/2*g*t^2,
Final height is the same as the initial = 0
0 = 11*7 +1/2*g*7^2 ---> g = -11*7*2/7^2 = -22/7 m/s^2
Minus because it goes down, You can say g_planet = 22/7 m/s^2 ~ 3.14 m/s^2. Earth's one on its surface is about 9.81 m/s^2, so this planet has 3 times less gravity. It may be 1/3 the radius of the Earth, assuming same density. This is not asked! :)
Answer:
33.33 m/s
Explanation:
m = 450 kg. T = 5000 N, t = 3 seconds,
let the net acceleration is a.
T = m a
a = 5000 / 450 = 11.11 m/s^2
u = 0 , v = ?
Let v be the velocity after 3 seconds.
Use first equation of motion
v = u + a t
v = 0 + 11.11 x 3 = 33.33 m/s