Question

By what distance do two objects carrying 1.0 C of charge each have to be separated before the electric force exerted on each object is 5.5 N

Answer 1

Answer:

Distance between both the object will be 404.51 m

Explanation:  

We have given charge on two objects $q_1=q_2=1C$

Coulomb force between the two objects is given F = 5.5 N

We have to fond the distance between both the object so that force between them is 5.5 N

According to coulomb law force between two charge particle is $F=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r^2}$

So $5.5=\frac{9\times 10^9\times 1\times 1}{r^2}$

$r^2=16.36\times 10^8$

r = 404.51 m

So distance between both object will be 404.51 m