The horizontal surface on which the block slides is frictionless.The speed of the block before it touches the spring is 6.0 m/s.
1 answer:
Answer:
V = 5.4 m/s
Explanation:
It is given that,
Let mass of the block, m = 10 kg
Spring constant of the spring, k = 2 kN/m = 2000 N/m
Speed of the block, v = 6 m/s
Compression in the spring, x = 15 cm = 0.15 m
Let V is the speed of the block moving at the instant the spring has been compressed 15 cm. It can be calculated using the conservation of energy of spring mass system.
V = 5.61 m/s
From the given options,
V = 5.4 m/s
Hence, this is the required solution.
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Answer:
The time for final 15 cm of the jump equals 0.1423 seconds.
Explanation:
The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as
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Applying the given values we get