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natima [27]
3 years ago
11

The James Webb Space Telescope will be the largest telescope ever put into space and will replace the Hubble Space Telescope. It

will be launched into orbit beyond Earth's moon, where it can work in an ultra-cold environment, protected from the heat of the Sun. How will the new technology of the Webb Telescope enhance the data scientists will be able to collect from outer space?
It will collect highly detailed data about nuclear activity deep within the Sun.


It will avoid the distortion from the atmosphere and give scientists more accurate data.


It will detect high-energy ultraviolet radiation emitted from supernovae and black holes.


It will see farther out into space to give scientists insight into how the Universe was formed.
Physics
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

B : It will avoid the distortion from the atmosphere and give scientists more accurate data

Explanation:

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The force of gravity considers which two parts?
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Mass of object/source
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Fg=mg
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3 years ago
A 70.0-kg person throws a 0.0480-kg snowball forward with a ground speed of 33.5 m/s. A second person, with a mass of 55.0 kg, c
saw5 [17]

Answer:

The final velocity of the thrower is \bf{3.88~m/s} and the final velocity of the catcher is \bf{0.029~m/s}.

Explanation:

Given:

The mass of the thrower, m_{t} = 70~Kg.

The mass of the catcher, m_{c} = 55~Kg.

The mass of the ball, m_{b} = 0.0480~Kg.

Initial velocity of the thrower, v_{it} = 3.90~m/s

Final velocity of the ball, v_{fb} = 33.5~m/s

Initial velocity of the catcher, v_{ic} = 0~m/s

Consider that the final velocity of the thrower is v_{ft}. From the conservation of momentum,

&& m_{t}v_{ft} + m_{b}v_{fb} = (m_{t} + m_{b})v_{it}\\&or,& v_{ft} = \dfrac{(m_{t} + m_{b})v_{it} - m_{b}v_{fb}}{m_{t}}\\&or,& v_{ft} = \dfrac{(70 + 0.0480)(3.90) - (0.0480)(33.5)}{70}\\&or,& v_{ft} = 3.88~m/s

Consider that the final velocity of the catcher is v_{fc}. From the conservation of momentum,

&& (m_{c} + m_{b})v_{fc} = m_{b}v_{it}\\&or,& v_{fc} = \dfrac{m_{b}v_{it}}{(m_{c} + m_{b})}\\&or,& v_{fc} = \dfrac{(0.048)(33.5)}{(55.0 + 0.0480)}\\&or,& v_{fc} = 0.029~m/s

Thus, the final velocity of thrower is 3.88~m/s and that for the catcher is 0.029~m/s.

8 0
3 years ago
Does the moon fall partly into earth's shadow when it is n "full"?
murzikaleks [220]
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5 0
4 years ago
An 8.5 kg crate is pulled 5.1 m up a 30 degree incline by a rope angled 17 degrees above the incline. The tension in the rope is
Ulleksa [173]

Answer:

1. a W_t=746.63 J

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  c W_n=183.96J

2. T_e=99.71J

Explanation:

a). The work done by the tension is:

W_t=T*dt

dt=\frac{5.1}{cos(17)}

W_t=140N*\frac{5.1}{cos(17)}

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b). The work done potential of gravity

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c). The work done by the normal force

W_n=N*d_n

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2. The increase in thermal energy is:

T_e=F*d

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F_k=19.5N

T_e=19.55*5.1m

T_e=99.71J

4 0
3 years ago
When two objects collide their momentum after the collision is explained by what?
Gnesinka [82]
<span>When two objects collide their momentum after the collision is explained by</span> the conservation of momentum
5 0
4 years ago
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