Answer:
The acceleration of the sliding toboggan is, a = 4.9 m/s²
Explanation:
Given data,
The total weight of the toboggan, W = 1300 N
The slope is, Ф = 30°
The acceleration of a body under the influence of the gravitational field does not depend on its mass, size and shape in the absence of the air resistance.
Therefore,
The acceleration of the toboggan is given by the formula,
a = g Sin Ф
Substituting the given values in the above equation,
a = 9.8 x Sin 30°
= 4.9 m/s²
Hence, the acceleration of the sliding toboggan is, a = 4.9 m/s²
Answer:
All of the above.
Explanation:
All of these steps are useful towards getting a job.
Answer:
A
Explanation:
The magnet can always attract other things.
Answer:
option (D)
Explanation:
Here initial rotation speed is given, final rotation speed is given and asking for time.
If we use
A) θ=θ0+ω0t+(1/2)αt2
For this equation, we don't have any information about the value of angular displacement and angular acceleration, so it is not useful.
B) ω=ω0+αt
For this equation, we don't have any information about angular acceleration, so it is not useful.
C) ω2=ω02+2α(θ−θ0)
In this equation, time is not included, so it is not useful.
D) So, more information is needed.
Thus, option (D) is true.
Answer:
1985kg
Explanation:
assuming that
pi =3.14
oil density = 950kg/ cubic meter
g= 9.8m/s
