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Lapatulllka [165]
2 years ago
13

Which statement correctly describes mass-energy equivalence? All energy in the universe will be converted to an equivalent amoun

t of mass. Mass can decrease in nuclear changes without the production of energy. All energy in the universe is a result of mass being converted into energy. A large amount of mass is equivalent to a small amount of energy.
Physics
1 answer:
olchik [2.2K]2 years ago
4 0

The statement 'all energy in the universe is a result of mass being converted into energy' correctly describes mass-energy equivalence.

<h3>What is mass-energy equivalence?</h3>

The expression mass-energy equivalence refers to the proportion of matter that can be converted into energy in the universe.

This mass-energy equivalence is an outcome of process of converting mass into energy.

In conclusion, the statement 'all energy in the universe is a result of mass being converted into energy' correctly describes mass-energy equivalence.

Learn more about mass-energy equivalence here:

brainly.com/question/3171044

#SPJ1

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A piece of wood is floating in a bathtub. A second piece of wood sits on top of the first piece, and does not touch the water. I
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Answer:

D

Explanation:

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4 years ago
In foot x-ray, what is the distance/FFD and Why?
MakcuM [25]

Answer and Explanation:

FFD is the distance between the film on which the image is obtained and the center of the anode tube. The magnification and resolution of the image depends on the FFd By varying the FFD we can change the magnification and resolution of the image. The standard FFD is about 100 centimeters.

New studies have found that by changing the FFD to 130 cm the radiation dosage reduces while the image quality remains practically the same.

5 0
3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
spin [16.1K]

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

f = f_{0}\frac{v + v_{o}}{v - v_{s}}        

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer  

v: is the speed of the sound = 343 m/s

v_{o}: is the speed of the observer = 0 (it is heard in the town)

v_{s}: is the speed of the source =?

The frequency of the train before slowing down is given by:

f_{b} = f_{0}\frac{v}{v - v_{s_{b}}}  (1)                  

Now, the frequency of the train after slowing down is:

f_{a} = f_{0}\frac{v}{v - v_{s_{a}}}   (2)  

Dividing equation (1) by (2) we have:

\frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}}

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}}   (3)  

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

v_{s_{b}} = 2v_{s_{a}}     (4)

Now, by entering equation (4) into (3) we have:

\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}}  

\frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}}

By solving the above equation for v_{s_{a}} we can find the speed of the train after slowing down:

v_{s_{a}} = 11.06 m/s

Finally, the speed of the train before slowing down is:

v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.                        

I hope it helps you!                                                        

7 0
3 years ago
The Doppler effect is the change in
anzhelika [568]

Yes indeed, that is a true statement.  Truer words are seldom written, and I could not agree with you more.

In case you are asking a question, I can kind of see how this might be a question if there is a blank after "... the change in ..." that is to be filled with one or more new words.

If that is the situation, then the blank can be filled with "frequency or wavelength" .

8 0
3 years ago
Read 2 more answers
What is a permanent magnet​
Wewaii [24]

Answer:

a magnet that retains its magnetic properties in the absence of an inducing field or current

6 0
3 years ago
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