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3 years ago

Please hurry!!!

1 answer:

3 0

First we need to know the equation which is P=mv
Use the formula- 3.2 kg x m/s = 762 x V
divide 762 in both side to get the v by itself
now we will have 0.004193971166 and lets round it!
then we will have the answer of .0042

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Consider the reaction.

BaLLatris [955]

Answer:

Explanation:

Consider the reaction.A(g)↽−−⇀Z(g)A

(

)

↽

−

⇀

(

)

The equilibrium constant,

, expresses the relationship between the concentrations of the species at equilibrium.

(g)

The energy of A-A bond in A is 98 kJ/mol. The energy of Z-Z bond in Z is 165 kJ/mol. Which statement about the reaction is correct?

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

5) The energy of A-A bond in A is greater than the energy of Z-Z bond in Z.

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

It is correct that the activation energy for Reaction ↽−+X(g)AX(g) is smaller than that for Reaction ⇀+AX(g)↽−, because AX is less stable than A or Z, so it takes less energy to break the weaker bond in AX.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

Option (2) is incorrect because, though the formation of AX requires energy, which is not needed for the formation of A or Z; however, the total energy required to break both A-A and Z-Z bonds (above) is more than the amount released when A and Z combine to form AX.

Option (3) is incorrect because the amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

8 0

3 years ago

Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 k

dybincka [34]

We must write down laws of conservation of momenta and energy.
For the law of conservation of momenta will we will use two axes. One will be x-axis that will correspond to the east, and the other one will be y-axis corresponding to the north. Jack will be marked as 1 and Jill will be marked as 2.
Law of conservation of energy:
$\frac{m_1v_1^2}{2}=\frac{m_1v'_1^2}{2}+ \frac{m_2v_2^2}{2}\\
m_2v_2^2=m_1v_1^2-m_1v_1'^2\\
v_2=\sqrt{\frac{m_1v_1^2-m_1v_1'^2}{m_2}$
This will give us Jill's velocity after the colision.
$v_2=6.43\frac{m}{s}$
Law of conservation of momenta:
$x: m_1v_1=m_1v_1'cos(34)+m_2v_2cos(\theta)\\
y: 0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\$
We will use the second equation to get the angle at which the Jill is traveling:
$0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
m_2v_2sin(\theta)=m_1v_1'sin(34)\\
sin(\theta)=\frac{m_1v_1'sin(34)}{m_2v_2}\\
\theta=sin^{-1}(\frac{m_1v_1'sin(34)}{m_2v_2})$
When we plug all the number we get:
$\theta=27.45^\circ$
Please note that this is the angle below the x-axis.

6 0

3 years ago

If two runners take the same amount of time to run a mile, they have the same __________.

Elan Coil [88]

None of the choices is correct.

If two runners take the same amount of time to run a mile,
they have the same average speed. But their velocities
are not the same unless both runners begin and end their
run at the same points.

Speed is (distance covered) divided by (time to cover the distance).

Velocity is not. It's something different.
'Velocity' is not just a bigger word for 'speed'.

3 0

3 years ago

Read 2 more answers

When you look out the window you can see constantly moving air. Air is cycled in order to reach equilibrium. Answer the followin

svet-max [94.6K]

So base on your question about the moving air and its is cycled in order to reach equilibrium the answer of the questions are the following
A. what are the two major characteristic that change when air is heated and cooled?
-temperature and molecular structure/ phase of the matter

B. how does these characteristics change the movement of air?
-if the air has lower temp the possibility that it will become heavier than with the higher
C. what is the name of the cycle that develop during these changes? Air cycle
D. why do the changes you describe in part B provide an example of a cycle? because of its molecular activity will increase

5 0

3 years ago

Read 2 more answers

Determine the density of an object that has a mass of 149.8 g and displaces 12.1 mL of water when placed in a graduated cylinder

Crazy boy [7]

Answer:

"12.4 g/mL" would be the right solution.

Explanation:

The given values are:

Mass of the object,

= 149.8 g

Volume of the object,