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marshall27 [118]
3 years ago
8

If you bang on a large metal gong with a stick, producing a loud sound that can be heard by your friend down the street, how doe

s this sound travel to your friend’s ear?
Banging the gong sets the metal particles in motion, these particles move through the air to your friend’s ear.

Banging the gong releases sound particles that travel as vibrations through the air to your friend’s ear.

Banging the gong vibrates the metal, which passes its energy to the air, sending a sound wave through the air to your friend’s ear.

Banging the gong creates air particles; these particles vibrate. Their energy travels through the air to your friend’s ear, but the air particles themselves do not move.
Chemistry
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

c

Explanation:

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Answer:

Mass = 14.3 g

Explanation:

Given data:

Mass of Mg(OH)₂  = 16.0 g

Mass of HCl = 11.0 g

Mass of MgCl₂ = ?

Solution:

Chemical equation:

Mg(OH)₂ + 2HCl    →   MgCl₂ + 2H₂O

Number of moles of Mg(OH)₂ :

Number of moles = mass/ molar mass

Number of moles = 16.0 g/ 58.3 g/mol

Number of moles = 0.274 mol

Number of moles of HCl :

Number of moles = mass/ molar mass

Number of moles = 11.0 g/ 36.5 g/mol

Number of moles = 0.301 mol

Now we will compare the moles of Mg(OH)₂  and HCl with MgCl₂.

                           Mg(OH)₂          :           MgCl₂

                                 1                 :               1

                                 0.274        :          0.274

                               HCl             :              MgCl₂

                                  2              :               1

                                0.301         :           1/2×0.301 = 0.150

The  number of moles of MgCl₂ produced by HCl are less so it will limiting reactant.

Mass of MgCl₂:

Mass = number of moles × molar mass

Mass = 0.150 ×  95 g/mol

Mass = 14.3 g

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Which of the following tools is not used for measurement?
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Describe the observation Robert Brown made.​
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Answer:

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Explanation:

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