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vichka [17]
3 years ago
15

Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1

J. What is the velocity of the ball at the given point? m/s
Physics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

2.5 m/s

Explanation:

Mechanical energy is the sum of the potential and kinetic energy.

E = PE + KE

E = mgh + ½mv²

172.1 J = (7.26 kg) (9.8 m/s²) (2.1 m) + ½ (7.26 kg) v²

v = 2.5 m/s

Mumz [18]3 years ago
6 0

Answer:

2.5 m/s

Explanation: i jus did this on edg. its right:)

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An object at rest increases its velocity to 10 m/s in 3 seconds. what is its acceleration?
Anna11 [10]

Answer:

30m

Explanation:

10m per second

there is 3 seconds

10 times 3 is 30

4 0
4 years ago
A swimmer takes 45 seconds to complete a 100-meter lap. Calculate the swimmer’s average speed.
g100num [7]
2.22 m/s. Average speed is Total distance over time it took. 100m/45s = 2.22m/s
5 0
3 years ago
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What are the similarities between EMS waves and mechanical waves?
irga5000 [103]

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eternal mangekyou sharingan

Explanation:

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3 years ago
A 75.0 kg object decelerates from a speed of 100 m/s to 50 m/s over an interval of 25 seconds. What was the net force acting upo
lukranit [14]

Assuming constant acceleration <em>a</em>, the object has undergoes an acceleration of

<em>a</em> = (50 m/s - 100 m/s) / (25 s) = -2 m/s²

Then the net force has a magnitude <em>F</em> such that, by Newton's second law,

<em>F</em> = (75.0 kg) <em>a</em>

<em>F</em> = (75.0 kg) (-2 m/s²)

<em>F</em> = -150 N

meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.

7 0
3 years ago
The Bohr model pictures a hydrogen atom in its ground state as a proton and an electron separated by the distance a0 = 0.529 × 1
Tpy6a [65]

Answer:

E = -8.23 ​​10⁻¹⁷ N / C

Explanation:

In the Bohr model, the electric potential for the ground state corresponding to the Bohr orbit is

         E = k q₁ q₂ / r²

in this case

q₁ is the charge of the proton and q₂ the charge of the electron

         E = - k e² / a₀²

let's calculate

         E = - 9 10⁹ (1.6 10⁻¹⁹)² / (0.529 10⁻¹⁰)²

         E = -8.23 ​​10⁻¹⁷ N / C

8 0
3 years ago
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