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vichka [17]
3 years ago
15

Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1

J. What is the velocity of the ball at the given point? m/s
Physics
2 answers:
max2010maxim [7]3 years ago
7 0

Answer:

2.5 m/s

Explanation:

Mechanical energy is the sum of the potential and kinetic energy.

E = PE + KE

E = mgh + ½mv²

172.1 J = (7.26 kg) (9.8 m/s²) (2.1 m) + ½ (7.26 kg) v²

v = 2.5 m/s

Mumz [18]3 years ago
6 0

Answer:

2.5 m/s

Explanation: i jus did this on edg. its right:)

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<em>well..</em>

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<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em>

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