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MrRissso [65]
3 years ago
15

Problem set 3 » (8) river swimming a swimmer heads directly across a river, swimming at her maximum speed of 1.30 m/s relative t

o the water. She arrives at a point 48.0 m downstream from the point directly across the river, 64.0 m wide. What is the speed of the river current?
Physics
1 answer:
jasenka [17]3 years ago
5 0

Velocity of swimmer across river = 1.30 m/s

Distance arrived downstream = 48 m

Width of river = 64 m

Time taken to cross river = \frac{Width of river}{Velocity across river}

                                          = \frac{64}{1.30} =49.23 s

Speed of river current = \frac{Distance arrived downstream}{Time taken to cross river}

                                     = \frac{48}{49.23} = 0.975 m/s

So, the river is flowing at a speed 0.975 m/s.

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In the two-slit experiment, for the condition of bright fringes, the value of m = +2 corresponds to a path difference of λ.
melisa1 [442]

Answer:

False

Explanation:

We know that if path difference is even multiple of wavelength then bright fringes are formed and if path difference is odd multiple of wavelength then dark fringes are formed .

For bright fringes

Path difference Δx = m λ

m = 0 , 2 , 4 , 6.......

If m = 2 then the path difference will be

Δx = 2 λ

therefore the above statement if false.

False

7 0
3 years ago
Complete the following:
Serga [27]

Answer:

the light will reflect parallel to the principal axis

8 0
2 years ago
A class 9 student booked his ticket to moon. His travel company
jasenka [17]

Answer: LET'S TAKE GRAVITY ON EARTH AS 10 N/KG AND ON MOON AS 0.6 N/KG

a) weight=15kgx10N/kg

               = 150N

b) weight=15x0.6=9N

c) mass=is the same so 15kg

d) mass is measured in kg, weight in NEWTONS OR KG M/S^{2}

e) when the gravitational force is zero

Explanation:

7 0
3 years ago
A shopping cart with two nice kids, rolls off a horizontal roof ledge that is 50
Alisiya [41]

Answer:

9.39 m/s

Explanation:

Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.

Assume the up direction is positive and the down direction is negative.

  • v₀ = 0 m/s
  • a = -9.8 m/s²
  • Δy = -50 m
  • t = ?

Find the constant acceleration equation that contains these four variables.

  • Δy = v₀t + 1/2at²  

Substitute known values into this equation.

  • -50 = (0)t + 1/2(-9.8)t²

Multiply and simplify.

  • -50 = -4.9t²

Divide both sides of the equation by -4.9.

  • 10.20408163 = t²

Square root both sides of the equation.

  • t = 3.194382825

Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.  

List out known variables in the x-direction.

  • v₀ = ?
  • t = 3.194382825 s
  • a = 0 m/s²
  • Δx = 30 m

Find the constant acceleration equation that contains these four variables.

  • Δx = v₀t + 1/2at²  

Substitute known values into the equation.

  • 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²

Multiply and simplify.

  • 30 = v₀ · 3.194382825

Divide both sides of the equation by 3.194382825.

  • v₀ = 9.391485505

The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.

8 0
3 years ago
Read 2 more answers
Which is not expecting acceleration?
Kamila [148]

1. Answer: A skydiver whose air resistance is equal to that of her weight.

A skydiver free falls under gravity but her rate of fall slows down due to drag -air resistance. when this air resistance becomes equal to her weight, the two get balanced and the body does not accelerate or decelerates.

2. Answer: Gravity

Contact forces are those which act when there is physical contact between two bodies. For example: normal force, tension and spring force.

Non-contact forces act between two bodies even when they are at a distance apart. For example: gravity, electric force, magnetic force etc.

3. Answer: The tendency of an object's motion to remain the same.

Inertia is a property of matter by virtue of which it tends to remain in its state of motion or rest. It does depend on mass of the object, more the mass, more is inertia. For example, cycle can be easily moved but we need real push hard for a car to move.

4. Answer: 254 N

The man pushes the box with 310 N force at an angle of  55 degrees to the horizontal.

we can write this in terms of horizontal (F cos \theta)and vertical component (F sin\theta).

Horizontal component: F_H=310 \times cos (55^o)= 178 N

Vertical component: F_v=310 \times sin (55^o)= 254 N

The vertical component would act towards the floor making the job more difficult to move the job.



7 0
3 years ago
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