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lorasvet [3.4K]
3 years ago
10

True or False: The dots are placed as

Chemistry
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer: True

Explanation:

rusak2 [61]3 years ago
5 0

Answer:

Chemical Bond (False)

Explanation:

A mutual electrical attraction between the nuclei and valence electrons of different atoms that binds the atoms together

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What does homogeneous and herogeneous mean?
serious [3.7K]
Homogeneous:

denoting a process involving substances in the same phase (solid, liquid, or gaseous).

Herogeneous:

of or denoting a process involving substances in different phases (solid, liquid, or gaseous).




7 0
3 years ago
Consider the following Reaction.
jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol


number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 =>  0.5246 moles

Molar mass of H3PO4 =  97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:


3 Mg(OH)2 + 2 H3PO4 --->  Mg3(PO4)2 + 6 H2O


3 mol of Mg(OH)2 reacts with 2 mol of H3PO4  ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation  .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation  :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2


= (1/3)*0.5246


= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass


= 0.1749 *  262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%


Hope that helps!




3 0
3 years ago
if 2.0 g of hydrogen sulfide, H2S(g) reacts with 5.0 g of sodium hydroxide what mass of the excess reactant is present when the
Ronch [10]

Answer: iits 9.g

Explanation:

7 0
3 years ago
At which part of a river would you have the best luck growing food?
krek1111 [17]

Answer:

B. Delta

Explanation:

3 0
3 years ago
Read 2 more answers
What mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid <br> H2SO4 + N2 = 2NH3
sveticcg [70]

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

7 0
3 years ago
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