Answer:
Foxes, and pine trees
Explanation:
Foxes have lots of fur on them and can survive cold and harsh winters. Pine tress are also found in this biome. (note this may or maybe right or wrong)
Answer:
1.40 M [OH⁻]
Explanation:
This compound dissociates into 3 ions, but since we are asked about [OH⁻], it's only 2. Therefore, multiply the molarity of the solution by the number of ions that [OH⁻] dissociates into:
2 × 0.70 M = 1.40 M
Hope this helps! Sorry that you got a link. Those are getting really annoying
<h3><u>Answer;</u></h3>
Atomic particles
The first step in the two-step process of making a solution is the breakdown of the solute source into <u>atomic particles</u>.
<h3><u>Explanation</u>;</h3>
- Solution is a homogeneous mixture of two or more substances uniformly dispersed throughout a single phase
- <em><u>The liquid component that makes up the largest part of a solution is called the solvent, and the substance that is dissolved is called the solute.</u></em>
- Unsaturated Solution is a solution that contains less solute than a saturated solution does and that is able to dissolve additional solute, while saturated Solution is a solution that cannot dissolve any more solute under the given conditions
Answer: The volume for 0.850 mol of 
from a solution is 1700 mL.
The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Explanation:
Molarity is the number of moles of solute present in a liter of solution.
- As given moles of are 0.850 mol and molarity of solution is 0.5 M. Hence, its volume is calculated as follows.
Therefore, the volume for 0.850 mol of from a solution is 1700 mL.
- As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.
So, volume for LiOH solution is calculated as follows.
Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.
Answer:
2H2S + 3O2 → 2SO2 + 2H2O
V(O2) = 48.4 L
p = 105 kPa = 1.036 atm
T = 190 + 273 = 463 K
Ideal gas law:
pV = nRT
n = \frac{pV}{RT}n=
RT
pV
R = 0.08206 L×atm/mol×K
n(O2) = \frac{1.036 \times 48.4}{0.08206 \times 463}=1.319 \; mol=
0.08206×463
1.036×48.4
=1.319mol
According to the reaction:
n(H2S) = \frac{2}{3}
3
2
n(O2) = \frac{2}{3} \times 1.319 = 0.8798 \;mol
3
2
×1.319=0.8798mol
V = \frac{nRT}{p} \\ V(H_2S) = \frac{0.8798 \times 0.08206 \times 463}{1.036}=32.26 \;LV=
p
nRT
V(H
2
S)=
1.036
0.8798×0.08206×463
=32.26L
Answer: 32.26 L
Explanation:
