Answer:
0.83m/s
Explanation:
Given parameters:
distance = 1000m
time taken = 20min
Unknown:
Speed of the walking person = ?
Solution:
To solve this problem;
Speed = 
Time taken should be in seconds;
1 min = 60s
20min = 20 x 60 = 1200s
Speed = 
= 0.83m/s
Answer:
The acceleration of the cart is 1.0 m\s^2 in the negative direction.
Explanation:
Using the equation of motion:
Vf^2 = Vi^2 + 2*a*x
2*a*x = Vf^2 - Vi^2
a = (Vf^2 - Vi^2)/ 2*x
Where Vf is the final velocity of the cart, Vi is the initial velocity of the cart, a the acceleration of the cart and x the displacement of the cart.
Let x = Xf -Xi
Where Xf is the final position of the cart and Xi the initial position of the cart.
x = 12.5 - 0
x = 12.5
The cart comes to a stop before changing direction
Vf = 0 m/s
a = (0^2 - 5^2)/ 2*12.5
a = - 1 m/s^2
The cart is decelerating
Therefore the acceleration of the cart is 1.0 m\s^2 in the negative direction.
Answer:
975 m/s^2
Explanation:
The formula for rate of acceleration is
(Final velocity - intial velocity)/ time taken
If you plug in your data you will get 975 m/s^2
(1600 m/s -1210 m/s )/.4 s = 975 m^2
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