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Serjik [45]
4 years ago
9

Which characteristics describe the human genetic code? Check all that apply. contains over 3 billion base pairs can only help un

derstand human genetics can help explain genetic diseases composed of 50,000 genes composed of 23 chromosome
Physics
2 answers:
kozerog [31]4 years ago
5 0

Answer:

The answer is A C and D

correct on Edge 2020

lidiya [134]4 years ago
3 0

Answer:

contains over 3 billion base pairs

can help explain genetic diseases

composed of 50,000 genes

A, C, D,

Explanation:

JUST TOOK THE TEST ON e d g e n i u t i t y

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Zach runs a 100-meter race. 7 seconds after the race started Zach is 35 meters from the starting line and reaches his max speed;
Angelina_Jolie [31]

Answer:MaxSpeed=8 m/s. Additional distance during z seconds after top speed is 8*z meters. Now the distance at 7+z seconds after the race starts is D=( 35+8*z) meters. For x ≥ 7 the time of the race, then  D=(35+(x-7)*8) meters is the distance traveled during that time.

Explanation:

First we are interested in calculating the top speed, that is constant. We know at 35 meters he reaches the top speed and this happens 7 seconds after the race started. Also he is at 75 meters from the starting line 12 seconds after the beginning, then we can use the definition of speed, in this case is constant, to get its value:  Speed=change in distance / change in time

Then Speed= (75-35)meters/(12-7)seconds = 40m/5s=8m/s. That is the topspeed=8 m/s  

Now from the 35 meters he runs at constant speed, then if we are told he runs z seconds and we are asked the distance he runs in that time, we know the distance at constant speed is D=V*t,

then D= 8m/s * z seconds=8z meters.

But here since the run is a 100 meters-race we have an upper bound for z, here he has left (100-35)=65 meters to run at 8m/s, then he can maximum run additional 8,125 second or 15,125 seconds in total for the race.

That is D=8*z meters, with z < 8,125 seconds, this is the additional distance he can run after reaching his top speed.

Now the distance at 7+z seconds after the race starts is D=( 35+8*z) meters, the first 35 m he runs until reaching his top speed and the rest of the distance at this speed.

for x the total time of the run at a given point, we are asked the distance he has traveled at that time, then we are also told x ≥ 7, then  D=(35+(x-7)*8) meters, we subtract the 7 initial seconds because they are already counted in the initial 35 meters.

7 0
4 years ago
The speed of a wave on a violin A string is 288 m/s and on the G string is 128 m/s. The force exerted on the ends of the string
Katyanochek1 [597]

Answer:

\dfrac{\mu_A}{\mu_G}=0.197

Explanation:

given,

Speed of a wave on violin A = 288 m/s

Speed on the G string = 128 m/s

Force at the end of string G  = 110 N

Force at the end of string A = 350 N

the ratio of mass per unit length of the strings (A/G). = ?

speed for string A

 v_A = \sqrt{\dfrac{F_A}{\mu_A}}.......(1)

speed for string G

 v_G = \sqrt{\dfrac{F_G}{\mu_G}}........(2)

Assuming force is same in both the string

now,

dividing equation (2)/(1)

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\dfrac{F_G}{\mu_G}}}{\sqrt{\dfrac{F_A}{\mu_A}}}

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{128}{288}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{\mu_A}{\mu_G}=0.197

5 0
3 years ago
How much heat is absorbed by 20g granite boulder as energy from the sun causes its temperature to chage from 10C to 29 c (Specif
Leno4ka [110]

Answer:

Q = 266 Joules

Explanation:

Given the following data;

Mass = 20g

Initial temperature = 10°C

Final temperature = 29°C

Specific heat capacity of granite = 0.1 Cal/g°C to J/g°C = 0.7J/g°C

To find the quantity of heat absorbed;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Substituting into the equation, we have;

Q = 20*0.7*(29-10)

Q = 14 * 19

Q = 266 Joules

6 0
3 years ago
Explain why a book placed on a table does not move?
kifflom [539]

Answer:

The force that the book exerts down on the table is equal to the force the table exerts upward.

Explanation:

I am 100% positive. That results in balanced forces which is why it does not move. If you did want it to move, you would apply unbalanced forces.

4 0
4 years ago
Read 2 more answers
A 0.180-kilogram car traveling at 0.80 m/s to the right collides with a 0.100-kilogram cart intially at rest. The carts lock tog
prohojiy [21]

0.51 m/s to the right.

<h3>Explanation</h3>

The two carts lock together. As a result, the collision is inelastic. Kinetic energy will not conserve. Still, momentum conserves.

What's the momentum <em>p</em> of the two carts?

Before the collisions:

  • p_1 = m_1 \cdot v_1 = 0.180 \times 0.80 = 0.144 \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1};
  • p_2 = m_2 \cdot v_2 = 0.
  • Sum of momentum: p = p_1 + p_2 = 0.144\; \text{kg} \cdot \text{m}\cdot \text{s}^{-1}.

Momentum conserves. As a result, p(\text{after collision}) = p(\text{before collision}) = 0.144 \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1}

Velocity is the same for the two carts after the collision. Let v denote that velocity.

p(\text{after collision}) = m_1\cdot v+ m_2 \cdot v = (m_1 + m_2) \cdot v.

v = \dfrac{p(\text{after collision})}{m_1 + m_2} \\ \phantom{v} = \dfrac{0.144}{0.180 + 0.100} \\ \phantom{v} = 0.51 \; \text{m}\cdot \text{s}^{-1}.

Direction of the movement will stay the same. Both cars are now moving to the right.

6 0
3 years ago
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