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3 years ago

Why is chopping carrots a physical change ?

2 answers:

7 0

Answer: Chopping or cutting is a physical change. Any change in size and shape is attributed as physical change. There is no formation of a new substance after chopping and the molecular component of the carrots stays the same. Therefore it is a physical change.

Explanation:

astra-53 [7]3 years ago

5 0

Answer: Chopping carrots is a chemical change because you aren't changing the property its substance, you are just chopping it up, there is no new substance being formed.

Explanation:

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How much force is needed to accelerate a 3kg book in 15m/s

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F=M×A
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3 years ago

A person runs with a constant velocity of 1.2 m/s for 30 seconds. how far do they travel?

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They will travel 36 m

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When a liquid is cooled, the kinetic energy of the particles ?

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3 years ago

A large fraction of the ultraviolet (UV) radiation coming from the sun is absorbed by the atmosphere. The main UV absorber in ou

elena55 [62]

Answer:

$3.2\times 10^{-7}\ m$ or 0.32 μm.

Explanation:

Given:

The radiations are UV radiation.

The frequency of the radiations absorbed (f) = $9.38\times 10^{14}\ Hz$

The wavelength of the radiations absorbed (λ) = ?

We know that, the speed of ultraviolet radiations is same as speed of light.

So, speed of UV radiation (v) = $3\times 10^8\ m/s$

Now, we also know that, the speed of the electromagnetic radiation is related to its frequency and wavelength and is given as:

$v=f\lambda$

Now, expressing the above equation in terms of wavelength 'λ', we have:

$\lambda=\frac{v}{f}$

Now, plug in the given values and solve for 'λ'. This gives,

$\lambda=\frac{3\times 10^8\ m/s}{9.38\times 10^{14}\ Hz}\\\\\lambda=3.2\times 10^{-7}\ m\\\\\lambda=3.2\times 10^{-7}\times 10^{6}\ \mu m\ [1\ m=10^6\ \mu m]\\\\\lambda=3.2\times 10^{-1}=0.32\ \mu m$

Therefore, the wavelength of the radiations absorbed by the ozone is nearly $3.2\times 10^{-7}\ m$ or 0.32 μm.

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3 years ago

Starting from rest, a car undergoes a constant acceleration of 6 m/s^2. How far will the car travel in the two seconds?

oksano4ka [1.4K]

If time is specified, the distance may be estimated in constant acceleration using the formula: X=(at2)/2 if the beginning velocity is 0. (A automobile begins from a stop...) As a result, X=(6*10*10)/2=600/2 = 300 m.

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2 years ago