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Zina [86]
3 years ago
7

A 0.05-kg car starts from rest at a height of 0.95 m. Assuming no friction, what is the kinetic energy of the car when it reache

s the bottom of the hill? (Assume g = 9.81 m/s2.)
A. 0.466 J
B. 0.308 J
C. 4.317 J
D. 0.0475 J

Physics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

The kinetic energy of the car when it reaches the bottom of the hill is about A. 0.466 J

\texttt{ }

<h3>Further explanation</h3>

<em>Let's recall </em><em>Kinetic Energy</em><em> Formula as follows:</em>

\large {\boxed{Ek = \frac{1}{2}mv^2} }

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

mass of the car = m = 0.05 kg

initial speed of toy car = u = 0 m/s

initial height position of the car = h₁ = 0.95 m

final height position of the car = h₂ = 0 m

gravitational acceleration = g = 9.81 m/s²

<u>Asked:</u>

final kinetic energy of the car = Ek₂ = ?

<u>Solution:</u>

<em>We will use </em><em>Conservation of Energy</em><em> to solve this problem:</em>

Ep_1 + Ek_1 = Ep_2 + Ek_2

mgh_1 + \frac{1}{2} m u^2 = mgh_2 + Ek_2

mgh_1 + \frac{1}{2} m (0)^2 = mg(0) + Ek_2

mgh_1 = Ek_2

Ek_2 = 0.05 \times 9.81 \times 0.95

Ek_2 \approx 0.466 \texttt{ J}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Energy

statuscvo [17]3 years ago
6 0
The kinetic energy of the car is A.) 0.466 J
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Un vas plin cu lichid cântăreşte 175kg. Ceea ce reprezintă de 5 ori masa vasului gol. Ştiind că volumul interior al vasului este
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a) Density of the liquid: 823.5kg/m^3

b) Weight of the liquid: 1372 N

Explanation:

Translation of the text:

<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>

<em>a) the density of the liquid; </em>

<em>b) the weight of the liquid."</em>

a)

We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as

M=m_L + m_V (1)

where

m_L is the mass of the liquid

m_V is the mass of the vessel

We also know that the total mass M is 5 times the mass of the empty vessel, so we have:

M=5m_V\\m_V=\frac{M}{5}=\frac{175}{5}=35 kg

which is the mass of the empty vessel.

Therefore, we can find the mass of the liquid only using (1):

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The density of the liquid is given by

d=\frac{m}{V}

where

m = 140 kg (mass of the liquid)

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So we get

d=\frac{140}{0.170}=823.5kg/m^3

b)

The weight of a body is given by

F=mg

where

m is its mass

g is the acceleration due to gravity

For the liquid in this problem, we have

m = 140 kg (mass)

g=9.8 m/s^2 (acceleration due to gravity)

Therefore, its weight is

F=(140)(9.8)=1372 N

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

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