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LenKa [72]
3 years ago
11

Three identical 50-kg masses are held at the corners of an equilateral triangle, 30 cm on each side. If one of the masses is rel

eased, what is its initial acceleration, if the only forces acting on it are the gravitational forces due to the other two masses?
A)1.9 x 10-8 m/s^2
B)6.4 x 10-8 m/s^2
C)4.2 x 10-8 m/s^2
D)2.5 x 10-8 m/s^2
E)3.7 x 10-8 m/s^2
Physics
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

a = 3.21 10⁻⁸ m / s² ,  The correct answer is E

Explanation:

For this exercise we will use Newton's second law, where the force is the gravitational attraction force, the attached diagram shows the forces and their components in a horizontal and vertical coordinate system, due to the symmetry of the equilateral triangle the horizontal components be annulled and the two vertical components add up; let's write Newton's education for the vertical axis (Y)

        2 F_{y} = m a

Let's use trigonometry to find the components

       sin 60 = F_{y}  / F

       F_{y}  = F sin60

     

      2 F sin60 = m a

The gravitational force equation is

     F = G m M / r

The mass of the entire sphere is equal to m = M and the distance between    the spheres is the side of the equilateral triangle

    F = G m² / L²

We replace

     2 (G m² / L²) sin60 = m a

     a = 2 G m / L² sin 60

Let's calculate

      a = 6.67 10⁻¹¹  50 / 0.30²  sin 60

      a = 3.21 10⁻⁸ m / s²

The correct answer is E

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Mars2501 [29]

Answer:

Hey Friend....

Explanation:

This is ur answer....

<h3><em>Transfer of energy by electromagnetic waves. Radiation doesn't require matter. Sunlight melting a wax crayon left outside is radiation.</em></h3><h3><em /></h3>

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5 0
2 years ago
The horse on a carousel is 3.5m from the central axis.A. If the carousel rotates at 0.13 rev/s , how long does it take the horse
Kitty [74]

Answer:

a. 15.4 seconds

b. 0.455 m/s

Explanation:

a. The carousel rotates at 0.13 rev/s.

This means that it takes the carousel 1 sec to make 0.13 of an entire revolution.

This means that time it will take to make a complete revolution is:

1 / 0.13 = 7.7 seconds

Therefore, the time it will take to make 2 revolutions is:

2 * 7.7 = 15.4 seconds

b. Let us calculate the linear velocity. Angular velocity is given as:

\omega = v / r

where v = linear velocity and r = radius

The radius of the circle is 3.5 m and the angular velocity is 0.13 rev/s, therefore:

0.13 = v / 3.5

v = 3.5 * 0.13 = 0.455 m/s

Linear velocity is 0.455 m/s

8 0
3 years ago
An Olympic track runner starts from rest and has an acceleration of 2.4 m/s2 for 3.6 s, then has zero acceleration for the remai
rjkz [21]

Answer:

The runner's speed at the following times would remain 8.64 m/s.

Explanation:

Acceleration definition: Acceleration is rate of change in velocity of an object with respect to time.

In this case, after 3.6 seconds the acceleration is zero, it means that the velocity of the runner after 3.6 seconds is not changing and it will remain constant for the remainder of the race. Now, we have to find the velocity of the runner that he had after 3.6 seconds and that would be the runner's speed for the remainder of the race. For this we use first equation of motion.

First equation of motion:        Vf = Vi + a×t

Vf stands for final velocity

Vi stands for initial velocity

a stands for acceleration

t stands for time

In the question, it is mentioned that the runner starts from rest so its initial velocity (Vi) will be 0 m/s.

The acceleration (a) is given as 2.4 m/s²

The time (t) is given as 3.6 s

Now put the values of Vi, a and t in first equation of motion

                       Vf = Vi + a×t

                       Vf = 0 + 2.4×3.6

                       Vf = 2.4×3.6

                       Vf = 8.64 m/s

So,the runner's speed at the following times would remain 8.64 m/s.

5 0
3 years ago
Where did beowulf and his warriors take the skull
dedylja [7]
I'm pretty sure Beowulf took the skull to Herot.
6 0
3 years ago
Joshua was driving to a friend’s house to study. During his trip, he started on pavement. At one point, he hit an ice patch on t
Tems11 [23]

Answer:

b. Friction decreased when he went from pavement to ice and then increased two more times.

Explanation:

Frictional force depends on the normal force of the surface and a friction coefficient.

F_{f} = -\mu N

Since we're talking about the same car, the value of N will remain constant whereas μ will represent the change in the frictional coefficient of the surface. Now we consider the different surfaces, cars will slide in an icy road which means that the frictional coefficient is smaller than the pavement.

After Joshua returns to the pavement road, the resulting frictional force increases and will do so one more time when he reaches the gravel road. Gravel roads have greater frictional coefficients than pavement roads which means the frictional force will increase a second time.

7 0
3 years ago
Read 2 more answers
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